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Interpretation:
It is to be explained why fluorine is smaller than oxygen and chlorine.
Concept Introduction :
Periodic trends are patterns found in the periodic table that show several facets of a particular element. A periodic trend is observed in atomic size also. Atomic size increases down the group.
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Explanation of Solution
Fluorine and oxygen are present in the same period and so have the same number of shells. However, because oxygen only has 8 protons pulling those outer electrons, fluorine has 9 protons, which will tend to make F slightly smaller in radius than O. The number of shells stays constant in F and O while the nuclear charge increases by one. As nuclear charge increases, electrons in the outermost shell are drawn to it with increasing force, which causes the size of atoms to gradually shrink over time.
Chlorine and fluorine are present in group 17 and chlorine is placed below fluorine. Down the group atomic size decreases. This is because when moving from top to bottom in the group, both the number of shells and nuclear charge increase. The effect of more shells, however, outweighs the effect of a higher nuclear charge which increases atomic radius.
Thus, fluorine has a smaller radius than oxygen and chlorine.
Chapter 6 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Deducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forwardPredict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward> Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forward
- Predict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward(EXM 2, PRBLM 3) Here is this problem, can you explain it to me and show how its done. Thank you I need to see the work for like prbl solving.arrow_forwardcan someone draw out the reaction mechanism for this reaction showing all bonds, intermediates and side products Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided belowarrow_forward
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