Calculate the overall energy change in kilojoules per mole for the formation of CsF(s) from its elements using the following data:
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- Calculate the lattice energy of potassium fluoride, KF, using the BornHaber cycle. Use thermodynamic data from Appendix C to obtain the enthalpy changes for each step. (Note: You will obtain a slightly different answer if you use values given in Chapter 8 for the ionization energy and electron affinity, which are energy values at 0 K rather than the enthalpy changes at 298 K.)arrow_forwardGiven the following enthalpy values for Na and Cl, calculate the lattice energy of NaCl using the Born- Haber cycle. for Na = 107.5 kJ/mole for Na = 495.8 kJ/mole for Cl, = 242.6 kJ/mole AHO sublimation AH ionization energy AHO dissociation energy ΔΗΡ electron affinity TOr Cl, = -348.6 kJ/mole AH formation for NaCl(s) = -4l1.2 kJ/molearrow_forward1. Below is a list of enthalpy changes for the Born-Haber cycle for the formation of solid LiF from Li(s) and F(g). Use these data to determine the lattice energy for the formation LiF(s). Li(s) → Li(g) ΔH1 = +162 kJ/mol Li(g) → Li+(g) + e- ΔH2 = +520.2 kJ/molF2(g) → 2F(g) ΔH3 = 154 kJ/mol F(g) + e- → F-(g) ΔH4 = -328 kJ/molLi(s) + 1/2F2(g) → LiF(s) ΔHf = -612 kJ/mol Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a. 1371 kJ/mol b. -1371 kJ/mol c. 1043 kJ/mol d. -1043 kJ/molarrow_forward
- Suppose there is an element X which occurs naturally as X2(g).X2(g) + 2O2(g) → X2O4(g)ΔHof of O(g) is 249 kJ/molΔHof of X(g) is 458.5 kJ/molΔHof of X2O4(g) is 31 kJ/molThe X-X single bond energy is 116 kJ/molUse the above data to estimate the average bond energy in X2O4. Give your answer to the nearest 1 kJ/mol.arrow_forwardConsider an ionic compound, MX3, composed of generic metal M and generic gaseous halogen X. The enthalpy of formation of MX3 is Δ?∘f=−925 kJ/mol. The enthalpy of sublimation of M is Δ?sub=175 kJ/mol. The first, second, and third ionization energies of M are IE1=579 kJ/mol, IE2=1677 kJ/mol, and IE3=2479 kJ/mol. The electron affinity of X is Δ?EA=−369 kJ/mol. (Refer to the hint). The bond energy of X2 is BE=179 kJ/mol. Determine the lattice energy of MX3.arrow_forwardConsider an ionic compound, MX, composed of generic metal M and generic, gaseous halogen X. • The enthalpy of formation of MX is AH; -517 kJ/mol. • The enthalpy of sublimation of M is AH sub = 141 kJ/mol. • The ionization energy of M is IE = 449 kJ/mol. • The electron affinity of X is AHEA = -323 kJ/mol. (Refer to the hint). • The bond energy of X, is BE = 217 kJ/mol. Determine the lattice energy of MX. AHjattice kJ/molarrow_forward
- 12 1) Which substance is expected to have the greatest lattice energy * CsCl LiF BaO Bacl, Rb20arrow_forwardConsider the following information. • The lattice energy of RbCl is AHjattice = -689 kJ/mol. t • The enthalpy of sublimation of Rb is AHsub = 80.9 kJ/mol. • The first ionization energy of Rb is IE, 403 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AHf, for RbCl(s). AHf = kJ/molarrow_forwardUse the data provided below to calculate the lattice energy of RbCl. Is this value greater or less than thelattice energy of NaCl? Explain.Electron affinity of Cl = –349 kJ/mol1st ionization energy of Rb = 403 kJ/molBond energy of Cl2 = 242 kJ/molSublimation energy of Rb = 86.5 kJ/molΔHf [RbCl (s)] = –430.5 kJ/molarrow_forward
- Consider an ionic compound, MXMX, composed of generic metal MM and generic, gaseous halogen XX. The enthalpy of formation of MXMX is Δ?∘f=−553ΔHf∘=−553 kJ/mol. The enthalpy of sublimation of MM is Δ?sub=129ΔHsub=129 kJ/mol. The ionization energy of MM is IE=491IE=491 kJ/mol. The electron affinity of XX is Δ?EA=−325ΔHEA=−325 kJ/mol. (Refer to the hint). The bond energy of X2X2 is BE=219BE=219 kJ/mol. Determine the lattice energy of MXMX. Δ?lattice=ΔHlattice= kJ/molarrow_forwardWhat is the chemical formula for the compound formed between manganese(IV) and chlorine? chemical formula: What is the chemical formula for the compound formed between manganese(IV) and sulfur? chemical formula:arrow_forwardThe energy for the following reaction was measured to be -653.0 kJ/mol. K(g) + Cl(g) → KCl(s). Using this fact and data in the table below, calculate the enthalpy (in kJ/mol) required to separate the ions from the lattice for this reaction: KCl(s) → K⁺(g) + Cl⁻(g).arrow_forward
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