Use the following information plus the data given in Tables6.2 and 6.3 to calculate the second
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LCPO CHEMISTRY W/MODIFIED MASTERING
- Which of the following compounds requires the most energy to convert one mole of the solid into separate ions? (a) MgO (b) SrO (c) KF (d) CsF (e) MgF2arrow_forwardCalculate the lattice energy of potassium fluoride, KF, using the BornHaber cycle. Use thermodynamic data from Appendix C to obtain the enthalpy changes for each step. (Note: You will obtain a slightly different answer if you use values given in Chapter 8 for the ionization energy and electron affinity, which are energy values at 0 K rather than the enthalpy changes at 298 K.)arrow_forwardUsing the standard enthalpy of formation data in Appendix G, calculate the bond energy of the carbon-sulfur double bond in CS2.arrow_forward
- Consider an ionic compound, MXMX, composed of generic metal MM and generic, gaseous halogen XX. The enthalpy of formation of MXMX is Δ?∘f=−411ΔHf∘=−411 kJ/mol. The enthalpy of sublimation of MM is Δ?sub=101ΔHsub=101 kJ/mol. The ionization energy of MM is IE=461IE=461 kJ/mol. The electron affinity of XX is Δ?EA=−325ΔHEA=−325 kJ/mol. (Refer to the hint). The bond energy of X2X2 is BE=189BE=189 kJ/mol. Determine the lattice energy of MXMX.arrow_forwardConsider an ionic compound, MXMX, composed of generic metal MM and generic, gaseous halogen XX. The enthalpy of formation of MXMX is Δ?∘f=−553ΔHf∘=−553 kJ/mol. The enthalpy of sublimation of MM is Δ?sub=105ΔHsub=105 kJ/mol. The ionization energy of MM is IE=483IE=483 kJ/mol. The electron affinity of XX is Δ?EA=−307ΔHEA=−307 kJ/mol. (Refer to the hint). The bond energy of X2X2 is BE=213BE=213 kJ/mol. Determine the lattice energy of MXMX. Δ?lattice=ΔHlattice= kJ/molarrow_forwardThe standard heat of formation of BaBr2BaBr2 is −−764 kJ/molkJ/mol. The first ionization energy of BaBa is 503 kJ/molkJ/mol and its second ionization energy is 965 kJ/molkJ/mol. The heat of sublimation of Ba[Ba(s)→Ba(g)]Ba[Ba(s)→Ba(g)] is 175 kJ/molkJ/mol. The bond energy of Br2Br2 is 193 kJ/molkJ/mol, the heat of vaporization of Br2(l)Br2(l) is 31 kJ/molkJ/mol, and the electron affinity of BrBr is −−325 kJ/molkJ/mol. Calculate the lattice energy of BaBr2BaBr2.arrow_forward
- Consider an ionic compound, MXMX, composed of generic metal MM and generic, gaseous halogen XX. The enthalpy of formation of MXMX is Δ?∘f=−553ΔHf∘=−553 kJ/mol. The enthalpy of sublimation of MM is Δ?sub=129ΔHsub=129 kJ/mol. The ionization energy of MM is IE=491IE=491 kJ/mol. The electron affinity of XX is Δ?EA=−325ΔHEA=−325 kJ/mol. (Refer to the hint). The bond energy of X2X2 is BE=219BE=219 kJ/mol. Determine the lattice energy of MXMX. Δ?lattice=ΔHlattice= kJ/molarrow_forwardUse the Born-Haber cycle to calculate the lattice energy of KF. [The heat of sublimation of K is 91.6 kJ·mol−1 and ΔfH(KF) = −567.3 kJ·mol−1. Bond enthalpy for F2 is 158.8 kJ·mol−1. Other data may be found in the Ionization Energies Table and the Electron Affinities Table.]arrow_forwardUsing the following data, calculate the lattice energy of calcium chloride: Ca2+(g) + 2Cl– (g) → CaCl2(s) ΔHlattice = ? Sublimation enthalpy of calcium ΔH = 177.8 kJ/mol First ionization energy of calcium ΔH = 590.2 kJ/mol Second ionization energy of calcium ΔH = 1144.2 kJ/mol First electron affinity of chlorine ΔH = –349 kJ/mol Heat of formation of CaCl2(s) ΔH = –795.4 kJ/mol Bond energy of Cl2 (see Table 2) Use Hess’s law to calculate the lattice energy of calcium chloride. set-up must show all the chemical equations and you must show how their H values add up to give your answer.arrow_forward
- The bond energy of N2 is 160 kJ/mol. What is the wavelength of a photon that can cause the dissociation of a N2 molecule? (h = 6.63 × 10–34J s; c = 3.0 × 108m/s and Avogadro's number = 6.022 × 1023 molecules/mole)arrow_forwardUsing the following data, estimate the overall enthalpy of formation (in kJ/mol) for potassium chloride: K(s) + ½ Cl₂(g) → KCI(s). Process Lattice energy of KCI lonization energy of K Electron affinity of Cl Bond dissociation energy of Cl, Enthalpy of sublimation for K Question 21 of 28 Change in Energy (AHO) -690 kJ/mol 419 kJ/mol -349 kJ/mol 239 kJ/mol 90 kJ/molarrow_forwardConsider the following data for nickel: atomic mass electronegativity electron affinity ionization energy heat of fusion 58.693 1.91 112. 737.1 g mol 17.2 kJ mol kJ mol kJ mol Does the following reaction absorb or release energy? (1) Ni (g) → Ni(g) + e Is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1): Does the following reaction absorb or release energy? (2) Ni' (g) + e Ni (g) - Is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above? If you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2): Orelease O absorb O Can't be decided with the data given. O yes O no kJ/mol O release O absorb O Can't be decided with the data given. O yes O no kJ/molarrow_forward
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