Interpretation:
Whether a cesium atom transfers an electron to a chlorine atom to form isolated
Concept introduction:
Ionization energy is amount of energy needed to eliminate electron from isolated, neutral gaseous atom. It is denoted by
Change in energy when electron is added to neutral isolated atom of gas is called
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LCPO CHEMISTRY W/MODIFIED MASTERING
- What is the electron configuration of the Ba3+ ion? Suggest a reason why this ion is not normally found in nature.arrow_forwardCompare the electron affinity of fluorine to the ionization energy of sodium. Does the process of an electron being pulled from the sodium atom to the fluorine atom have a negative or a positive E? Why is NaF a stable compound? Does the overall formation of NaF have a negative or a positive E? How can this be?arrow_forwardOf the five elements Sn, Si, Sb, O, Te, which has the most endothermic reaction? (E represents an atom.) What name is given to the energy for the reaction? E(g)E+(g)+earrow_forward
- The lattice energy of an ionic solid such as NaCl is the enthalpy change H for the process in which the solid changes to ions. For example, NaCl(s)Na+(g)+Cl(g)H=786kJ/mol Assume that the ionization energy and electron a affinity are H values for the processes defined by those terms. The ionization energy of Na is 496 kJ/mol. Use this, the electron affinity from Table 8.4, and the lattice energy of NaCl to calculate H for the following process: Na(g)+Cl(g)NaCl(s)arrow_forwardThe lattice energy of potassium iodide is the energy required for the following reaction. KI(s) → K+(g) + I−(g) ΔHrxn = ΔHlattice Use the Born-Haber cycle to calculate ΔHlattice for KI(s) from the information given below. Equation 1: 2 K(s) + I2(g) → 2 KI(s) ΔH1 = −655 kJ/mol Equation 2: K(s) → K(g) ΔH2 = 89 kJ/mol Equation 3: I2(g) → 2 I(g) ΔH3 = 214 kJ/mol Equation 4: K(g) → K+(g) + e− ΔH4 = 419 kJ/mol Equation 5: I(g) + e− → I−(g) ΔH5 = −294 kJ/molarrow_forward8. Given the following information: Li(s) HI(g) → H(g) + I(g) enthalpy of sublimation of Li(s) = 166 kJ/mol bond energy of HI = 295 kJ/mol Li(g) Li(g) → Li"(g) + e ionization energy of Li(g)= 520. kJ/mol I(g) + e — Г(g) electron affinity of I(g) = -295 kJ/mol Li"(g) + I(g) → LiI(s) lattice energy of LiI(s) = -737 kJ/mol H2(g) → 2H(g) Calculate the change in enthalpy for: bond energy of H2 = 432 kJ/mol 2Li(s) + 2HI(g) –→ H2(g) + 2LİI(s) a. 330 kJ b. –534 kJ c. -483 kJ d. -984 kJ e. none of thesearrow_forward
- Write electron configurations for the following ions of main group elements: (a) N3−, (b) Ba2+, and (c) Be2+.arrow_forwardConsider an ionic compound, MXMX, composed of generic metal MM and generic, gaseous halogen XX. The enthalpy of formation of MXMX is Δ?∘f=−411ΔHf∘=−411 kJ/mol. The enthalpy of sublimation of MM is Δ?sub=101ΔHsub=101 kJ/mol. The ionization energy of MM is IE=461IE=461 kJ/mol. The electron affinity of XX is Δ?EA=−325ΔHEA=−325 kJ/mol. (Refer to the hint). The bond energy of X2X2 is BE=189BE=189 kJ/mol. Determine the lattice energy of MXMX.arrow_forwardConsider the following information. The enthalpy of formation of SrO is Δ?∘f =−592.0 kJ/mol. The enthalpy of sublimation of Sr is Δ?sub =164.4 kJ/mol. The first and second ionization energies of Sr are IE1=549 kJ/mol and IE2=1064 kJ/mol. The first electron affinity of O is Δ? EA1=−142 kJ/mol. The bond energy of O2 is BE =498 kJ/mol. The lattice energy of SrO is Δ? lattice=−3217 kJ/mol. Determine the second electron affinity of O.arrow_forward
- what is be2+ valence electron configuration?arrow_forwardGiven: Enthalpy of atomisation of calcium =+ 178 kJ First ionisation energy of calcium =+590 kJ Second ionisation energy of calcium = +1145 kJ Enthalpy of atomisation of chlorine =+ 121 kJ Electron affinity of chlorine Lattice energy of calcium chloride =- 2258 kJ = - 346 kJ Construct a Born-Haber cycle for calcium chloride, CaCl2 by using the data given above. Hence, calculate the enthalpy of formation of calcium chloride. b. The enthalpy of solution for calcium chloride crystal is -81.3 kJ mol'. Based on the data from the above Born-Haber cycle, calculate the enthalpy change for the reaction below: Ca" (g) + 2CI (g)–→ Ca* (aq) + 2CI¯ (aq)arrow_forwardConsider a hypothetical ionic compound AB (comprised of A* and B ions). Given the following enthalpy data and using a Born-Haber cycle calculation, predict AHiattice in kJ mol. AG) + Bs) - AB 4H = -384 kJ mol As) → Ag) ArH = 105 kJ mol B(s) - Bg) A,H = 101 kJ mol1 First ionization energy of Ag) = 501 kJ mol" Answes=? Electron affinity enthalpy of Bro (exothermic) = -348 kJ molarrow_forward
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- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax