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LCPO CHEMISTRY W/MODIFIED MASTERING
- For which of the following substances is the least energy required to convert one mole of the solid into separate ions? (a) MgO (b) SrO (c) KF (d) CsF (e) MgF2arrow_forwardWhich compound in each of the following pairs of ionic substances has the most negative lattice energy? Justify your answers. a. LiF, CsF b. NaBr, NaI c. BaCl2, BaO d. Na2SO4, CaSO4 e. KF, K2O f. Li2O, Na2Sarrow_forwardArrange the following series of compounds in order of increasing lattice energies. (a) NaBr, NaCl, KBr (b) MgO, CaO, CaCl2 (c) LiF, BeF2, BeOarrow_forward
- Think of forming an ionic compound as three steps (this is a simplification, as with all models): (I) removing an electron from the metal; (2) adding an electron to the nonmetal; and (3) allowing the metal cation and nonmetal anion to come together. a. What is the sign of the energy change for each of these three processes? b. In general, what is the sign of the sum of the first two processes? Use examples to support your answer. c. What must be the sign of the sum of the three process d. Given your answer to part c, why do ionic bonds occur? e. Given your above explanations, why is NaCl stable but not Na2Cl? NaCl2? What about MgO compared to MgO2? Mg2O?arrow_forwardConsider the reactions of silver metal, Ag(s), with each of the halogens: fluorine, F2(g), chlorine, Cl2(g), and bromine, Br2(l). What chapter data could you use to decide which reaction is most exothermic? Which reaction is that?arrow_forwardDraw the Born-Haber cycle for the formation of solid sodium chloride and use the following data to calculate the lattice energy. Na(s) → Na(g) ΔH° = 109 kJ/mol Cl2(g) → 2Cl(g) ΔH° = 243 kJ/mol Na(g) → Na+(g) + e- ΔH° = 496 kJ/mol Cl(g) + e- → Cl-(g) ΔH° = -349 kJ/mol Na(s) + 1/2Cl2(g) → NaCl(s) ΔH° = -411 kJ/molarrow_forward
- Enter your answer in the provided box. Use the Born-Haber cycle to calculate the lattice energy of NaCl. (The heat of sublimation of Na is 108 kJ/mol and AH (NaCl) = -411 kJ/mol. Energy needed to dissociate 1/2 mole of Cl, into Cl atoms = 121.4 kJ.) kJ/molarrow_forward1. Caleulate the lattice energy of LiF, given the following: Li(s) + %F:(g) → LiF(s) AH =-617 kJ AH = -520 kJ Li"(g) + e(g) → Li(g) Li(s) →Li(g) F(g) → F(g) + e (g) F:(g) →2F(g) AH = 161 kJ AH = 328 kJ AH = 154 kJarrow_forwardCyanamide is a compound containing two hydrogen atoms and some amount of C and N. There are a total of 5 atoms in the compound. The products of combustion were found to be CO2, NO2, and H2O. If the enthalpy of combustion for cyanamide is – 671.9 kJ/mol and the enthalpy of formation is 58.8 kJ/mol, what is the chemical formula for cyanamide? ( ΔfH (CO2) = - 393.51 kJ/mole; ΔfH (NO2) = + 33.10 kJ/mole; ΔfH (H2O) = - 241.826 kJ/mole)arrow_forward
- The lattice energy of NaCl is 769 kJ/mole. Which of the following is a correct statement about NaCl? When one mole each of gaseous Nat and CI- ions form solid NaCl, 769 kJ of heat is consumed. It requires 769 kJ to separate one mole of solid NaCl into one mole of each gaseous Na* and CI- ions. It requires 769 kJ to separate one mole of solid NaCl into gaseous one mole of Na* and two moles of CI- ions.arrow_forwardneed help with the lattice energyarrow_forwardUse the data in the table below to calculate the lattice energy of KCI. K(s) → K(g) K(g) → K+ (g) + e¯ Cl₂(g) → Cl(g) Cl(g) + e Cl¯ (g) → K(s) + ½Cl₂(g) → KCl(s) 155.2 90.0 kJ/mol 418.8 kJ/mol 122 kJ/mol -349 kJ/mol -437 kJ/molarrow_forward
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