The ground-state electron configuration for the following ion should be determined: Ni 2 + Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively. All the suborbital can have maximum of 2 electrons with opposite spins.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. NaO :0: Select to Add Arrows THF > Plea

app aktv.com Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :0: 0:0 H NaO Select to Add Arrows CH3CH2CCNa Problem 31 of 35 Please select a

K Sepp aktiv com Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Drawing Arrows CH3CH2OK, CH3CH2OH Altis Learning App 31 Problem 28 of 35 H. :0: H H H H H 0:0 H KO Undo Reset Done

Answer 2

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Answer 6

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Answer 7

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Answer 8

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Answer 13

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Answer 14

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Answer 15

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3