Given Information : The given code is: //variable declaration //matrix Int x[2][128]; int i; //variable to store sum Int sum=0; //iterate through the matrix for(i=0;i<128;i++) { //sum of matrix elements sum+= x[0][i]*x[1][i]; } Explanation: The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses. Here, size of (int) =4. Only memory accesses entries of array “x”. C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Question

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Answer 1

Question

Chapter 6, Problem 6.36HW

A)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

B)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

C)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

D)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

     {

//sum of matrix elements

              sum+= x[0][i]*x[1][i];

     }

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

E)

Program Plan Intro

Given Information:

The given code is:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Students have asked these similar questions

Please solve this problem in emu8086 microprocessor in Assembly Language. Please solve properly, will upvote after getting proper solve Read 10 inputs (range 0-9) from the user and store them in an array. Find the position (or index) of the maximum and minimum values in the array, and swap them (move the biggest element to the position of the smallest, and move the smallest element to the position of the biggest), and print that again. If there are multiple maximum or minimum numbers, then choose the first occurrence, values. Your program should be able to handle negative values. Explanation: Here from the given input we see that 9 is the maximum number and it has occurred twice, first in the 2nd index and again in the 5th index. Similarly here 3 is the least and it also has appeared twice, once in the 3rd index and again in the 6th index. So we swap 9 and 3 from the 2nd and 3rd indices and then after swapping, print the new array. Input: 7935935874 Output: 7395645874 Comment:Range 0…

80x86 Intel Assembly language Write an 80x86 Intel assembly language program: Declare two integer arrays and initialize the first one with 7, 6, 5, 4 and 3. Initialize the second one with 3, 6, 9, 10, 15 Declare the third array of the same size but do not initialize. Your program must initialize ESI and EDI to have the addresses of the array1 and array2 respectively. Use EBX and place the address of the third array in that register. Use these registers to add the first element of the first array to the first element of the second array and place the result in the third array. Updated the values of these registers so all of them refer to the next location.

Microprocessor 8086 write An array called (A) has 300 unsigned byte numbers (chose your Owen data), write only one assemble to the following1-store the Maximum number of (A) in physical address AB200h. 2- store the Minimum number of (A) in the physical address CD100h. 3-rearrange the array given (A) ascending and save the new array in the memory starting at 3050e 4-save only the maximum odd number in the logical address 5200:0350

Answer 2

Question

Chapter 6, Problem 6.36HW

A)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

B)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

C)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

D)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

     {

//sum of matrix elements

              sum+= x[0][i]*x[1][i];

     }

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

E)

Program Plan Intro

Given Information:

The given code is:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 6, Problem 6.36HW

A)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

B)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

C)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

D)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

     {

//sum of matrix elements

              sum+= x[0][i]*x[1][i];

     }

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

E)

Program Plan Intro

Given Information:

The given code is:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 6, Problem 6.36HW

A)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

B)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

C)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

D)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

     {

//sum of matrix elements

              sum+= x[0][i]*x[1][i];

     }

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

E)

Program Plan Intro

Given Information:

The given code is:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 6, Problem 6.36HW

A)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

B)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

C)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

D)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

     {

//sum of matrix elements

              sum+= x[0][i]*x[1][i];

     }

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

E)

Program Plan Intro

Given Information:

The given code is:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 6

Chapter 6, Problem 6.36HW

A)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 7

Chapter 6, Problem 6.36HW

A)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 8

B)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 9

B)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 10

C)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 11

C)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 12

D)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

     {

//sum of matrix elements

              sum+= x[0][i]*x[1][i];

     }

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 13

D)

Program Plan Intro

Given Information:

The given code is:

//variable declaration

//matrix

int x[2][128];

int i;

//variable to store sum

int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

     {

//sum of matrix elements

              sum+= x[0][i]*x[1][i];

     }

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 14

E)

Program Plan Intro

Given Information:

The given code is:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 15

E)

Program Plan Intro

Given Information:

The given code is:

The given code is:

//variable declaration

//matrix

Int x[2][128];

int i;

//variable to store sum

Int sum=0;

//iterate through the matrix

for(i=0;i<128;i++)

{

//sum of matrix elements

sum+= x[0][i]*x[1][i];

}

Explanation:

The given array is x[2][128]. The cache is initially empty and it begins to store data from “0x0” addresses.

Here, size of (int) =4.

Only memory accesses entries of array “x”.

C arrays allocated in row-major order which means that each row is in their contiguous memory location.

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 19

Ch. 6.1 - Prob. 6.1PP Ch. 6.1 - Prob. 6.2PP Ch. 6.1 - Prob. 6.3PP Ch. 6.1 - Prob. 6.4PP Ch. 6.1 - Prob. 6.5PP Ch. 6.1 - Prob. 6.6PP Ch. 6.2 - Prob. 6.7PP Ch. 6.2 - Prob. 6.8PP Ch. 6.4 - Prob. 6.9PP Ch. 6.4 - Prob. 6.10PP

Solution Summary: The author explains that the given array is x[2][128]. The cache is initially empty and it begins to store data from "0x0" addresses.

Concept explainers

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Chapter 6 Solutions