Chapter 5.2, Problem 15R

To determine

To calculate: The amount of solar energy falls on the house each second.

Answer to Problem 15R

Solar energy falls is $S=63072\times {10}^3{\text{J/m}}^2$

Explanation of Solution

Given data:

Radiation from sun, $R=200\text{ W}$

Length of the house, $L=10\text{ m}$

Width of the house, $B=10\text{ m}$

Time period, $T=1\text{ year = 31536000 s}$

Formula used:

Energy in joules ( E ),

  $E=R\times T$

Area of the house ( A ),

  $A=L\times B$

Solar energy fall on the house ( S ),

  $S=E\times A$

Calculation:

Energy in joules ( E ),

  $\begin{array}{l}E=200\times 31536000\\ E=6307200000\end{array}$

Area of the house ( A ),

  $\begin{array}{l}A=L\times B\\ A=10\times 10=100{\text{ m}}^2\end{array}$

Solar energy falls on the house ( S ),

  $\begin{array}{l}S=E\times A\\ S=\frac{6307200000}{100}\\ S=63072\times {10}^3{\text{J/m}}^2\end{array}$

Conclusion:

Hence, the solar energy falls on the house is $S=63072\times {10}^3{\text{J/m}}^2$ .