Chapter 5, Problem 46R

To determine

The specific heat of material.

Answer to Problem 46R

  $C=450\text{J/kg}°\text{C}$

Explanation of Solution

Given:

Energy, $E=6750\text{J}$

Mass, $m=3\text{ kg}$

Temperature, $\Delta T=5°\text{C}$

Formula used:

Thermal energy can be calculated as:

  $Q=mc\left(\Delta T\right)$

Where,

  $m$ = mass

  $c$ = Heat capacity

  $\left(\Delta T\right)$ = change in temperature

Calculation:

  $\begin{array}{l}Q=mc\Delta T\\ c=\frac{6750}{3\times 5}\\ C=450\text{J/kg}°\text{C}\end{array}$

Conclusion:

Heat capacity is $c=450\text{J/kg}°\text{C}$