Chapter 5, Problem 6STP

To determine

To Choose: The correct option.

Answer to Problem 6STP

Option A: $Q=187\text{ J}$

Explanation of Solution

Given data:

Mass of the block of aluminum, $M=24.5\text{ g = 0}\text{.0245 g }$

Initial temperature, $T_i=21.5°\text{C}$

Final temperature, $T_f=30°\text{C}$

Specific heat, $S=897\text{ J/kg}°\text{C}$

Formula used:

Change in the thermal energy ( Q ),

  $Q=M\times S\times (T_f-T_i)$

Calculation:

Change in the thermal energy ( Q ),

  $\begin{array}{l}Q=M\times S\times (T_f-T_i)\\ Q=0.0245\times 897\times (30-21.5)\\ Q=0.0245\times 897\times 8.5\\ Q=186.800\text{ J = 187 J}\end{array}$

Conclusion:

Hence, the change in the thermal energy of aluminum block is $Q=187\text{ J}$ .