Chapter 5.1, Problem 2PP

To determine

To compute the specific heat of the block.

Answer to Problem 2PP

  $S=200\text{ J/(kg}°\text{C)}$

Explanation of Solution

Given data:

Mass of bock, $M=2\text{ kg}$

Thermal energy, $Q=2000\text{ J}$

Change in the temperature, $\Delta T=5°\text{C}$

Formula used:

Specific heat ( S ),

  $Q=M\times S\times (\Delta T)$

Calculation:

Specific heat ( S ),

  $\begin{array}{l}Q=M\times S\times (\Delta T)\\ S=\frac{Q}{M\times \Delta T}\\ S=\frac{2000}{2\times 5}\\ S=200\text{ J/(kg}°\text{C)}\end{array}$

Conclusion:

The specific heat is $S=200\text{ J/(kg}°\text{C)}$ .