Make sure to draw a Free Body Diagram as well 7.6. A crate of mass M starts from rest at the top of a frictionless rampinclined at an angle a above the horizontal. Find its speed at the bottomof the ramp, a distance d from where it started. Do this in two ways: Takethe level at which the potential energy is zero to be (a) at the bottom ofthe ramp with y positive upward, and (b) at the top of the ramp with y pos-itive upward. (c) Why didn't the normal force enter into your solution?

The free body diagram of the object is given below.The forces acting on the object areNormal…

Answered: 7.6. A crate of mass M starts from rest…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter6: Energy Of A System

Section: Chapter Questions

Problem 8CQ

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In a Coyote/Road Runner cartoon clip (https://openstaxcollege.org/l/21coyroadcarcl), a spring expands quickly and sends the coyote into a rock. If the spring extended 5 m and sent the coyote of mass 20 kg to a speed of 15 m/s, (a) what is the spring constant of this spring? (b) If the coyote were sent vertically into the air with the energy given to him by the spring, how high could he go if there were no non-conservative forces?
A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance?
Check Your Understanding The spring Example 7.5 is compressed 6 cm from its equilibrium length. (a) Does the spring force do positive or negative work and (b) what is the magnitude?
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In an iconic movie scene, Forrest Gump (https://openstaxcollege.org/l/21ForrGumpvid) runs around the country. If he is running at a constant speed of 3 m/s, would it take him more or less energy to run uphill or downhill and why?
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Describe a situation in 4iich a force is exerted for a long time but does no work. Explain.
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A particle moving in the xy -plane is subject to a force F(x,y)=(50Nm2)(xi+yj)( x 2 + y 2 )3/2 , where x and y are in meters. Calculate the work done on the particle by this force, as it moves in a straight line from the point (3 in, 4 m) to the point (8 in, 6 in).
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