The molar enthalpy of vaporization of benzene at its normal boiling point (80.09°C) is 30.72 kJ/mol. Assuming that AvapH and AvapS stay constant at their values at 80.09°C, calculate the value of AvapG at 75.0°C, 80.09°C, and 85.0°C. Hint: Remember that the liquid and vapor phases will be in equilibrium at the normal boiling point.
The molar enthalpy of vaporization of benzene at its normal boiling point (80.09°C) is 30.72 kJ/mol. Assuming that AvapH and AvapS stay constant at their values at 80.09°C, calculate the value of AvapG at 75.0°C, 80.09°C, and 85.0°C. Hint: Remember that the liquid and vapor phases will be in equilibrium at the normal boiling point.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter19: Temperature, Thermal Expansion And Gas Laws
Section: Chapter Questions
Problem 61PQ
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Transcribed Image Text:The molar enthalpy of vaporization of benzene at its normal boiling point (80.09°C) is 30.72 kJ/mol.
Assuming that AvapH and AvapS stay constant at their values at 80.09°C, calculate the value of
AvapG at 75.0°C, 80.09°C, and 85.0°C.
Hint: Remember that the liquid and vapor phases will be in equilibrium at the normal boiling point.
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