Data Table 1: Coefficient of Static Friction for Wooden Block using Applied Force Trial Mass, M, [kg] Hanging Mass, m [kg] Coefficient of Static m Friction, μs= M 1 0.38 0.33 kg 0.127 kg 2 0.33 kg 0.13 kg 0.39 3 0.33 kg 0.13 kg 0.39 4 0.33 kg 0.13 kg 0.39 Average: M = 0.33 kg, m = 0.129 kg, μs= 0.39 Data Table 2 Coefficient of Static Friction for Largest Surface Area Side using Applied Force, 10 washers. M = Mass of Wooden Block + Plastic Beaker + Six Large Washers: [enter answer] [kg] Trial Mass, M, [kg] Hanging Mass, m [kg] Coefficient of Static m Friction, μs= M 1 0.52 kg 0.214 kg 0.41 2 0.52 kg 0.214 kg 0.41 3 0.52 kg 0.214 kg 0.41 0.52 kg 0.214 kg 0.41 Average: M = 0.52 kg, m = 0.214 kg, μs=0.41
Data Table 1: Coefficient of Static Friction for Wooden Block using Applied Force Trial Mass, M, [kg] Hanging Mass, m [kg] Coefficient of Static m Friction, μs= M 1 0.38 0.33 kg 0.127 kg 2 0.33 kg 0.13 kg 0.39 3 0.33 kg 0.13 kg 0.39 4 0.33 kg 0.13 kg 0.39 Average: M = 0.33 kg, m = 0.129 kg, μs= 0.39 Data Table 2 Coefficient of Static Friction for Largest Surface Area Side using Applied Force, 10 washers. M = Mass of Wooden Block + Plastic Beaker + Six Large Washers: [enter answer] [kg] Trial Mass, M, [kg] Hanging Mass, m [kg] Coefficient of Static m Friction, μs= M 1 0.52 kg 0.214 kg 0.41 2 0.52 kg 0.214 kg 0.41 3 0.52 kg 0.214 kg 0.41 0.52 kg 0.214 kg 0.41 Average: M = 0.52 kg, m = 0.214 kg, μs=0.41
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Should the results of your experimental Coefficient of Static Friction for the Wooden Block for the wooden block (Data Table 1) and the wooden block with the added mass (Data Table 2) be similar? Explain why or why not. Determine whether the results of the experiment are within a reasonable experimental error (< 10%) by calculating the % difference.
Please help with showing how to calculate and with explaination, I'm not sure. Thanks!
![Data Table 1: Coefficient of Static Friction for Wooden Block using Applied Force
Trial
Mass, M, [kg]
Hanging Mass, m [kg] Coefficient of Static
m
Friction, μs= M
1
0.38
0.33 kg
0.127 kg
2
0.33 kg
0.13 kg
0.39
3
0.33 kg
0.13 kg
0.39
4
0.33 kg
0.13 kg
0.39
Average: M = 0.33 kg, m = 0.129 kg, μs= 0.39
Data Table 2
Coefficient of Static Friction for Largest Surface Area Side using Applied Force, 10 washers.
M = Mass of Wooden Block + Plastic Beaker + Six Large Washers: [enter answer] [kg]
Trial
Mass, M, [kg]
Hanging Mass, m [kg] Coefficient of Static
m
Friction, μs= M
1
0.52 kg
0.214 kg
0.41
2
0.52 kg
0.214 kg
0.41
3
0.52 kg
0.214 kg
0.41
0.52 kg
0.214 kg
0.41
Average: M = 0.52 kg, m = 0.214 kg, μs=0.41](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc993bc3d-2ca5-48d7-9d6f-b44db78b61ed%2Ff5ea2c9f-a021-43c2-8dcf-4a6ac41c3efa%2F7fbkuvs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Data Table 1: Coefficient of Static Friction for Wooden Block using Applied Force
Trial
Mass, M, [kg]
Hanging Mass, m [kg] Coefficient of Static
m
Friction, μs= M
1
0.38
0.33 kg
0.127 kg
2
0.33 kg
0.13 kg
0.39
3
0.33 kg
0.13 kg
0.39
4
0.33 kg
0.13 kg
0.39
Average: M = 0.33 kg, m = 0.129 kg, μs= 0.39
Data Table 2
Coefficient of Static Friction for Largest Surface Area Side using Applied Force, 10 washers.
M = Mass of Wooden Block + Plastic Beaker + Six Large Washers: [enter answer] [kg]
Trial
Mass, M, [kg]
Hanging Mass, m [kg] Coefficient of Static
m
Friction, μs= M
1
0.52 kg
0.214 kg
0.41
2
0.52 kg
0.214 kg
0.41
3
0.52 kg
0.214 kg
0.41
0.52 kg
0.214 kg
0.41
Average: M = 0.52 kg, m = 0.214 kg, μs=0.41
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