Sodium cyclopentadienide, NaC 2 H 2, is a common reducing agent in the chemical laboratory, but there is a problem using it: NaC 2 H 2, is contaminated tetrahydrofuran ( THF ) , C 4 H 2 O, a solvent used in its preparation. The THFis present as NaC 2 H 2, (THF)2 and it is generally necessary to know how much of this NaC 2 H 2, ( THF ) 2 is present. This is accomplished by allowing a small amount of the to react with water. NaC 5 H 5 ⋅ ( C 4 H 8 O ) z +H 2 O → NaOH ( aq ) +C 5 H 4 - H+xC 4 H 8 O followed by titration of the NaOH(aq) with standard acid. From the sample data tabulated below, determine the value of x formula NaC 5 H 5 ⋅ ( THF ) z .
Sodium cyclopentadienide, NaC 2 H 2, is a common reducing agent in the chemical laboratory, but there is a problem using it: NaC 2 H 2, is contaminated tetrahydrofuran ( THF ) , C 4 H 2 O, a solvent used in its preparation. The THFis present as NaC 2 H 2, (THF)2 and it is generally necessary to know how much of this NaC 2 H 2, ( THF ) 2 is present. This is accomplished by allowing a small amount of the to react with water. NaC 5 H 5 ⋅ ( C 4 H 8 O ) z +H 2 O → NaOH ( aq ) +C 5 H 4 - H+xC 4 H 8 O followed by titration of the NaOH(aq) with standard acid. From the sample data tabulated below, determine the value of x formula NaC 5 H 5 ⋅ ( THF ) z .
Solution Summary: The author explains the formula of sodium cyclopentadienide contaminated with tetrahydrofuran.
Sodium cyclopentadienide,
NaC
2
H
2,
is a common reducing agent in the chemical laboratory, but there is a problem using it:
NaC
2
H
2,
is contaminated tetrahydrofuran
(
THF
)
, C
4
H
2
O,
a solvent used in its preparation. The THFis present as
NaC
2
H
2,
(THF)2 and it is generally necessary to know how much of this
NaC
2
H
2,
(
THF
)
2
is present. This is accomplished by allowing a small amount of the to react with water.
NaC
5
H
5
⋅
(
C
4
H
8
O
)
z
+H
2
O
→
NaOH
(
aq
)
+C
5
H
4
- H+xC
4
H
8
O
followed by titration of the NaOH(aq) with standard acid. From the sample data tabulated below, determine the value of x formula
NaC
5
H
5
⋅
(
THF
)
z
.
Question 4
Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
First-order, k = 0.210 hour 1
First-order, k = 0.0912 hour 1
O Second-order, k =
0.590 M1 hour 1
O Zero-order, k = 0.0770 M/hour
O Zero-order, k = 0.4896 M/hour
O Second-order, k = 1.93 M-1-hour 1
10 pts
Determine the rate order and rate constant for sucrose hydrolysis.
Time (hours)
[C6H12O6]
0
0.501
0.500
0.451
1.00
0.404
1.50
0.363
3.00
0.267
Draw the products of the reaction shown below. Use wedge and dash bonds
to indicate stereochemistry. Ignore inorganic byproducts.
OSO4 (cat)
(CH3)3COOH
Select to Draw
ઘ
Chapter 5 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
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