The active ingredients h a particular antacid tablets are aluminum hydroxide, Al ( OH ) 2 , and magnesium hydroxide, Mg ( OH ) 2 . A 5.00 × 10 2 sample of the active ingredients was dissolved in mL of 0.500 M HCI. The resulting solution, which was still acidic, required 16.5 mL of 0.377 M NaOH for neutralization. What are the mass percentages of Al ( OH ) 2 , and Mg ( OH ) 2 in the sample?
The active ingredients h a particular antacid tablets are aluminum hydroxide, Al ( OH ) 2 , and magnesium hydroxide, Mg ( OH ) 2 . A 5.00 × 10 2 sample of the active ingredients was dissolved in mL of 0.500 M HCI. The resulting solution, which was still acidic, required 16.5 mL of 0.377 M NaOH for neutralization. What are the mass percentages of Al ( OH ) 2 , and Mg ( OH ) 2 in the sample?
Solution Summary: The author describes titration as a method of quantitative analysis used to determine the concentration of unknown solutions.
The active ingredients h a particular antacid tablets are aluminum hydroxide,
Al
(
OH
)
2
,
and magnesium hydroxide,
Mg
(
OH
)
2
. A 5.00 × 102 sample of the active ingredients was dissolved in mL of 0.500 M HCI. The resulting solution, which was still acidic, required 16.5 mL of 0.377 M NaOH for neutralization. What are the mass percentages of
Al
(
OH
)
2
,
and
Mg
(
OH
)
2
in the sample?
I have a excitation/emission spectra of a quinine standard solution here, and I'm having trouble interpreting it. the red line is emission the blue line is excitation. i'm having trouble interpreting properly. just want to know if there is any evidence of raman or rayleigh peaks in the spectra.
Give the major product of the following reaction.
excess
1. OH, H₂O
1.OH
H
CH3CH2CH21
H
2. A.-H₂O
Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and
Advanced Template toolbars. The single bond is active by default.
2. Use Hess's law to calculate the AH
(in kJ) for:
rxn
CIF(g) + F2(g) →
CIF 3 (1)
using the following information:
2CIF(g) + O2(g) →
Cl₂O(g) + OF 2(g)
AH = 167.5 kJ
ΔΗ
2F2 (g) + O2(g) → 2 OF 2(g)
2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g)
о
=
= -43.5 kJ
AH = 394.1kJ
Chapter 5 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
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