Concept explainers
(a)
Interpretation:
The IUPAC name for the ester given has to be assigned.
Concept Introduction:
For naming an ester, it can be structurally viewed in a way that contains an acyl group and an alkyl group.
Rules to obtain IUPAC name and common name for an ester:
- Alkyl part appears first in the IUPAC name and it is followed by the acyl part of ester as a separate word.
- Name of the alkyl part in the ester is just a name of R group. It can be alkyl, cycloalkyl, or aryl group.
- Acyl part present in the ester is named by considering the acid name and replacing the suffix “-ic acid” with “-ate”.
- To obtain the common name the alkyl part name is the same while the acyl part name is derived from the common name of the acid by replacing the suffix “-ic acid” with “-ate”.
In line-angle structural formula, the point where two lines intersect and the end point represent a carbon atom.
(b)
Interpretation:
The IUPAC name for the ester given has to be assigned.
Concept Introduction:
For naming an ester, it can be structurally viewed in a way that contains an acyl group and an alkyl group.
Rules to obtain IUPAC name and common name for an ester:
- Alkyl part appears first in the IUPAC name and it is followed by the acyl part of ester as a separate word.
- Name of the alkyl part in the ester is just a name of R group. It can be alkyl, cycloalkyl, or aryl group.
- Acyl part present in the ester is named by considering the acid name and replacing the suffix “-ic acid” with “-ate”.
- To obtain the common name the alkyl part name is the same while the acyl part name is derived from the common name of the acid by replacing the suffix “-ic acid” with “-ate”.
In line-angle structural formula, the point where two lines intersect and the end point represent a carbon atom.
(c)
Interpretation:
The IUPAC name for the ester given has to be assigned.
Concept Introduction:
For naming an ester, it can be structurally viewed in a way that contains an acyl group and an alkyl group.
Rules to obtain IUPAC name and common name for an ester:
- Alkyl part appears first in the IUPAC name and it is followed by the acyl part of ester as a separate word.
- Name of the alkyl part in the ester is just a name of R group. It can be alkyl, cycloalkyl, or aryl group.
- Acyl part present in the ester is named by considering the acid name and replacing the suffix “-ic acid” with “-ate”.
- To obtain the common name the alkyl part name is the same while the acyl part name is derived from the common name of the acid by replacing the suffix “-ic acid” with “-ate”.
In line-angle structural formula, the point where two lines intersect and the end point represent a carbon atom.
(d)
Interpretation:
The IUPAC name for the ester given has to be assigned.
Concept Introduction:
For naming an ester, it can be structurally viewed in a way that contains an acyl group and an alkyl group.
Rules to obtain IUPAC name and common name for an ester:
- Alkyl part appears first in the IUPAC name and it is followed by the acyl part of ester as a separate word.
- Name of the alkyl part in the ester is just a name of R group. It can be alkyl, cycloalkyl, or aryl group.
- Acyl part present in the ester is named by considering the acid name and replacing the suffix “-ic acid” with “-ate”.
- To obtain the common name the alkyl part name is the same while the acyl part name is derived from the common name of the acid by replacing the suffix “-ic acid” with “-ate”.
In line-angle structural formula, the point where two lines intersect and the end point represent a carbon atom.
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Chapter 5 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forwardA mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forward
- Provide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forwardWhat units (if any) does K have? Does K depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)? in calculating the response factorarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Don't used Ai solution and don't used hand raitingarrow_forwardOA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forwardDon't used hand raitingarrow_forward
- Quizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
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