(a)
Interpretation:
The IUPAC name of reaction products when ethyl pentanoate undergoes ester hydrolysis under acidic conditions has to be written.
Concept Introduction:
Breaking of the carbon‑oxygen single bond present between the “acid part” and “alcohol part” is one of the important reactions of ester. This process of breaking the bond between the carbon‑oxygen is known as ester hydrolysis or saponification. The condition prevails in the reaction determines it as ester hydrolysis of saponification.
Ester hydrolysis takes place in ester when it is treated with strong acid or enzymes as catalyst. Reverse of esterification reaction is the ester hydrolysis.
Saponification is the reaction that ester undergoes when a strong base is used to give the product as
(a)
Answer to Problem 5.130EP
The IUPAC names of the products obtained are,
Explanation of Solution
Given name of ester is ethyl pentanoate. The structure of ethyl pentanoate can be given as,
Under acidic conditions, esters undergo hydrolysis resulting in breakage of the carbon‑oxygen single bond that is present between the “acid part” and “alcohol part”. The product that is obtained on ester hydrolysis in acidic conditions is carboxylic acid and an alcohol. The complete reaction and the structure of the product obtained can be written as shown below,
The IUPAC names of the product obtained can be given using
IUPAC names of the products obtained when ethyl pentanoate undergoes hydrolysis under acidic condition are written.
(b)
Interpretation:
The IUPAC name of reaction products when ethyl methanoate undergoes ester hydrolysis under acidic conditions has to be written.
Concept Introduction:
Breaking of the carbon‑oxygen single bond present between the “acid part” and “alcohol part” is one of the important reactions of ester. This process of breaking the bond between the carbon‑oxygen is known as ester hydrolysis or saponification. The condition prevails in the reaction determines it as ester hydrolysis of saponification.
Ester hydrolysis takes place in ester when it is treated with strong acid or enzymes as catalyst. Reverse of esterification reaction is the ester hydrolysis.
Saponification is the reaction that ester undergoes when a strong base is used to give the product as carboxylic acid salt and alcohol.
(b)
Answer to Problem 5.130EP
The structural formula and IUPAC names of the products obtained are,
Explanation of Solution
Given name of ester is ethyl methanoate. The structure of ethyl methanoate can be given as,
Under acidic conditions, esters undergo hydrolysis resulting in breakage of the carbon‑oxygen single bond that is present between the “acid part” and “alcohol part”. The product that is obtained on ester hydrolysis in acidic conditions is carboxylic acid and an alcohol. The complete reaction and the structure of the product obtained can be written as shown below,
The IUPAC names of the product obtained can be given using IUPAC nomenclature of naming the compounds. The IUPAC names and the structure of the product obtained are,
IUPAC names of the products obtained when ethyl methanoate undergoes hydrolysis under acidic condition are written.
(c)
Interpretation:
The IUPAC name of reaction products when isopropyl pentanoate undergoes ester hydrolysis under acidic conditions has to be written.
Concept Introduction:
Breaking of the carbon‑oxygen single bond present between the “acid part” and “alcohol part” is one of the important reactions of ester. This process of breaking the bond between the carbon‑oxygen is known as ester hydrolysis or saponification. The condition prevails in the reaction determines it as ester hydrolysis of saponification.
Ester hydrolysis takes place in ester when it is treated with strong acid or enzymes as catalyst. Reverse of esterification reaction is the ester hydrolysis.
Saponification is the reaction that ester undergoes when a strong base is used to give the product as carboxylic acid salt and alcohol.
(c)
Answer to Problem 5.130EP
The structural formula and IUPAC names of the products obtained are,
Explanation of Solution
Given name of ester is isopropyl pentanoate. The structure of isopropyl pentanoate can be given as,
Under acidic conditions, esters undergo hydrolysis resulting in breakage of the carbon‑oxygen single bond that is present between the “acid part” and “alcohol part”. The product that is obtained on ester hydrolysis in acidic conditions is carboxylic acid and an alcohol. The complete reaction and the structure of the product obtained can be written as shown below,
The IUPAC names of the product obtained can be given using IUPAC nomenclature of naming the compounds. The IUPAC names and the structure of the product obtained are,
IUPAC names of the products obtained when isopropyl pentanoate undergoes hydrolysis under acidic condition are written.
(d)
Interpretation:
The IUPAC name of reaction products when isopropyl methanoate undergoes ester hydrolysis under acidic conditions has to be written.
Concept Introduction:
Breaking of the carbon‑oxygen single bond present between the “acid part” and “alcohol part” is one of the important reactions of ester. This process of breaking the bond between the carbon‑oxygen is known as ester hydrolysis or saponification. The condition prevails in the reaction determines it as ester hydrolysis of saponification.
Ester hydrolysis takes place in ester when it is treated with strong acid or enzymes as catalyst. Reverse of esterification reaction is the ester hydrolysis.
Saponification is the reaction that ester undergoes when a strong base is used to give the product as carboxylic acid salt and alcohol.
(d)
Answer to Problem 5.130EP
The structural formula and IUPAC names of the products obtained are,
Explanation of Solution
Given name of ester is isopropyl methanoate. The structure of isopropyl methanoate can be given as,
Under acidic conditions, esters undergo hydrolysis resulting in breakage of the carbon‑oxygen single bond that is present between the “acid part” and “alcohol part”. The product that is obtained on ester hydrolysis in acidic conditions is carboxylic acid and an alcohol. The complete reaction and the structure of the product obtained can be written as shown below,
The IUPAC names of the product obtained can be given using IUPAC nomenclature of naming the compounds. The IUPAC names and the structure of the product obtained are,
IUPAC names of the products obtained when isopropyl methanoate undergoes hydrolysis under acidic condition are written.
Want to see more full solutions like this?
Chapter 5 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Don't used hand raiting and don't used Ai solutionarrow_forwardDon't used Ai solution and don't used hand raitingarrow_forwardOA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forward
- Don't used hand raitingarrow_forwardQuizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardQ3: Arrange each group of compounds from fastest SN2 reaction rate to slowest SN2 reaction rate. CI Cl H3C-Cl CI a) A B C D Br Br b) A B C Br H3C-Br Darrow_forwardQ4: Rank the relative nucleophilicity of halide ions in water solution and DMF solution, respectively. F CI Br | Q5: Determine which of the substrates will and will not react with NaSCH3 in an SN2 reaction to have a reasonable yield of product. NH2 Br Br Br .OH Brarrow_forward
- Classify each molecule as optically active or inactive. Determine the configuration at each H соон Chirality center OH 애 He OH H3C Ноос H H COOH A K B.arrow_forwardQ1: Rank the relative nucleophilicity of the following species in ethanol. CH3O¯, CH3OH, CH3COO, CH3COOH, CH3S Q2: Group these solvents into either protic solvents or aprotic solvents. Acetonitrile (CH3CN), H₂O, Acetic acid (CH3COOH), Acetone (CH3COCH3), CH3CH2OH, DMSO (CH3SOCH3), DMF (HCON(CH3)2), CH3OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co