EBK ORGANIC AND BIOLOGICAL CHEMISTRY
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
7th Edition
ISBN: 9780100547742
Author: STOKER
Publisher: YUZU
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Chapter 5, Problem 5.7EP

(a)

Interpretation Introduction

Interpretation:

The “C−Z” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 1

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 2

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 3

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(a)

Expert Solution
Check Mark

Answer to Problem 5.7EP

The “C−Z bond is polar.

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 4

Explanation of Solution

The general structure of carboxylic acid derivatives is,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 5

The atom in entity Z that is bonded to the carbonyl carbon atom is not a carbon atom.  It is a nitrogen atom.  As there is a polarity difference between carbon and nitrogen atom, the bond between carbon and nitrogen will be polar.  This can be shown as given below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 6

Conclusion

The “C−Z” bond is polar or not is indicated.

(b)

Interpretation Introduction

Interpretation:

The “C−Z” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 7

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 8

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 9

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(b)

Expert Solution
Check Mark

Answer to Problem 5.7EP

The “C−Z bond is nonpolar.

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 10

Explanation of Solution

The general structure of carboxylic acid derivatives is,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 11

The atom in entity Z that is bonded to the carbonyl carbon atom is a carbon atom.  As there is no polarity difference between carbon and carbon atom, the bond between carbon and carbon will be nonpolar.  This can be shown as given below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 12

Conclusion

The “C−Z” bond is polar or not is indicated.

(c)

Interpretation Introduction

Interpretation:

The “C−Z” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 13

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 14

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 15

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(c)

Expert Solution
Check Mark

Answer to Problem 5.7EP

The “C−Z bond is polar.

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 16

Explanation of Solution

The general structure of carboxylic acid derivatives is,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 17

The atom in entity Z that is bonded to the carbonyl carbon atom is an oxygen atom.  As there is a polarity difference between carbon and oxygen atom, the bond between carbon and oxygen will be polar.  This can be shown as given below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 18

Conclusion

The “C−Z” bond is polar or not is indicated.

(d)

Interpretation Introduction

Interpretation:

The “C−Z” bond in the general formula of carboxylic derivative is polar or nonpolar has to be indicated.

Concept Introduction:

Carbonyl groups are the one which contain a double bond between carbon and oxygen atom.  Aldehydes and ketones possess this carbonyl functional group in it.  The structural representation of a carbonyl group can be given as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 19

If a hydroxyl group is attached to a carbonyl group means it is known as carboxyl group.  This can be represented as shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 20

Carboxylic acid derivatives are the ones that are synthesized from or converted to a carboxylic acid.  The generalized structural representation of carboxylic acid derivatives is shown below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 21

In the carboxylic acid derivatives, if the carbonyl carbon atom is bonded to a more electronegative atom means, then the bond will be polar and is it is bonded to carbon atom means then it will be nonpolar.

(d)

Expert Solution
Check Mark

Answer to Problem 5.7EP

The “C−Z bond is polar.

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 22

Explanation of Solution

The general structure of carboxylic acid derivatives is,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 23

The atom in entity Z that is bonded to the carbonyl carbon atom is an oxygen atom.  As there is a polarity difference between carbon and oxygen atom, the bond between carbon and oxygen will be polar.  This can be shown as given below,

EBK ORGANIC AND BIOLOGICAL CHEMISTRY, Chapter 5, Problem 5.7EP , additional homework tip 24

Conclusion

The “C−Z” bond is polar or not is indicated.

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Chapter 5 Solutions

EBK ORGANIC AND BIOLOGICAL CHEMISTRY

Ch. 5.1 - Prob. 1QQCh. 5.1 - Prob. 2QQCh. 5.1 - Prob. 3QQCh. 5.1 - Prob. 4QQCh. 5.1 - Prob. 5QQCh. 5.2 - Prob. 1QQCh. 5.2 - Prob. 2QQCh. 5.2 - Prob. 3QQCh. 5.2 - Prob. 4QQCh. 5.2 - Prob. 5QQ
Ch. 5.3 - Prob. 1QQCh. 5.3 - Prob. 2QQCh. 5.3 - Prob. 3QQCh. 5.4 - Prob. 1QQCh. 5.4 - Prob. 2QQCh. 5.4 - Prob. 3QQCh. 5.5 - Prob. 1QQCh. 5.5 - Prob. 2QQCh. 5.5 - Prob. 3QQCh. 5.6 - Prob. 1QQCh. 5.6 - Prob. 2QQCh. 5.7 - Which of the following statements about acid...Ch. 5.7 - Prob. 2QQCh. 5.7 - Prob. 3QQCh. 5.8 - Prob. 1QQCh. 5.8 - Prob. 2QQCh. 5.8 - Prob. 3QQCh. 5.8 - Prob. 4QQCh. 5.9 - Prob. 1QQCh. 5.9 - Prob. 2QQCh. 5.10 - Prob. 1QQCh. 5.10 - Prob. 2QQCh. 5.11 - Prob. 1QQCh. 5.11 - Prob. 2QQCh. 5.11 - Prob. 3QQCh. 5.12 - Prob. 1QQCh. 5.12 - Prob. 2QQCh. 5.12 - Prob. 3QQCh. 5.12 - Prob. 4QQCh. 5.13 - Prob. 1QQCh. 5.13 - Prob. 2QQCh. 5.14 - Prob. 1QQCh. 5.14 - Prob. 2QQCh. 5.14 - Prob. 3QQCh. 5.15 - Prob. 1QQCh. 5.15 - Prob. 2QQCh. 5.15 - Prob. 3QQCh. 5.16 - Prob. 1QQCh. 5.16 - Prob. 2QQCh. 5.16 - Prob. 3QQCh. 5.17 - Prob. 1QQCh. 5.17 - Prob. 2QQCh. 5.18 - Prob. 1QQCh. 5.18 - Prob. 2QQCh. 5.18 - Prob. 3QQCh. 5.19 - Prob. 1QQCh. 5.19 - Prob. 2QQCh. 5.19 - Prob. 3QQCh. 5.19 - Prob. 4QQCh. 5.20 - Prob. 1QQCh. 5.20 - Prob. 2QQCh. 5.20 - Prob. 3QQCh. 5.20 - Prob. 4QQCh. 5 - Prob. 5.1EPCh. 5 - Prob. 5.2EPCh. 5 - Prob. 5.3EPCh. 5 - Indicate whether or not each of the compounds in...Ch. 5 - Prob. 5.5EPCh. 5 - Prob. 5.6EPCh. 5 - Prob. 5.7EPCh. 5 - Prob. 5.8EPCh. 5 - Prob. 5.9EPCh. 5 - Prob. 5.10EPCh. 5 - Prob. 5.11EPCh. 5 - Prob. 5.12EPCh. 5 - Prob. 5.13EPCh. 5 - Prob. 5.14EPCh. 5 - Prob. 5.15EPCh. 5 - Assign an IUPAC name to each of the following...Ch. 5 - Prob. 5.17EPCh. 5 - Prob. 5.18EPCh. 5 - Prob. 5.19EPCh. 5 - Prob. 5.20EPCh. 5 - Prob. 5.21EPCh. 5 - Prob. 5.22EPCh. 5 - Prob. 5.23EPCh. 5 - Prob. 5.24EPCh. 5 - Prob. 5.25EPCh. 5 - Prob. 5.26EPCh. 5 - Prob. 5.27EPCh. 5 - Prob. 5.28EPCh. 5 - Prob. 5.29EPCh. 5 - Prob. 5.30EPCh. 5 - Prob. 5.31EPCh. 5 - Prob. 5.32EPCh. 5 - Prob. 5.33EPCh. 5 - Prob. 5.34EPCh. 5 - Prob. 5.35EPCh. 5 - Prob. 5.36EPCh. 5 - Prob. 5.37EPCh. 5 - Prob. 5.38EPCh. 5 - Prob. 5.39EPCh. 5 - Prob. 5.40EPCh. 5 - Determine the maximum number of hydrogen bonds...Ch. 5 - Prob. 5.42EPCh. 5 - Prob. 5.43EPCh. 5 - Prob. 5.44EPCh. 5 - Prob. 5.45EPCh. 5 - Prob. 5.46EPCh. 5 - Prob. 5.47EPCh. 5 - Prob. 5.48EPCh. 5 - Prob. 5.49EPCh. 5 - Prob. 5.50EPCh. 5 - Prob. 5.51EPCh. 5 - Prob. 5.52EPCh. 5 - Prob. 5.53EPCh. 5 - Prob. 5.54EPCh. 5 - Draw structural formulas for the following...Ch. 5 - Prob. 5.56EPCh. 5 - Give the IUPAC name for each of the following...Ch. 5 - Give the IUPAC name for each of the following...Ch. 5 - Prob. 5.59EPCh. 5 - Prob. 5.60EPCh. 5 - Prob. 5.61EPCh. 5 - Prob. 5.62EPCh. 5 - Prob. 5.63EPCh. 5 - Prob. 5.64EPCh. 5 - Prob. 5.65EPCh. 5 - Which three carboxylic acids have salts that are...Ch. 5 - Prob. 5.67EPCh. 5 - Which carboxylic acid has salts that are used to...Ch. 5 - Prob. 5.69EPCh. 5 - Prob. 5.70EPCh. 5 - Prob. 5.71EPCh. 5 - Prob. 5.72EPCh. 5 - Prob. 5.73EPCh. 5 - Prob. 5.74EPCh. 5 - Prob. 5.75EPCh. 5 - Prob. 5.76EPCh. 5 - Prob. 5.77EPCh. 5 - Prob. 5.78EPCh. 5 - Prob. 5.79EPCh. 5 - Prob. 5.80EPCh. 5 - Prob. 5.81EPCh. 5 - Prob. 5.82EPCh. 5 - Prob. 5.83EPCh. 5 - Prob. 5.84EPCh. 5 - Prob. 5.85EPCh. 5 - Prob. 5.86EPCh. 5 - Prob. 5.87EPCh. 5 - Prob. 5.88EPCh. 5 - Prob. 5.89EPCh. 5 - Prob. 5.90EPCh. 5 - Assign common names to each of the esters in...Ch. 5 - Prob. 5.92EPCh. 5 - Prob. 5.93EPCh. 5 - Assign an IUPAC name to each of the following...Ch. 5 - Draw a structural formula for each of the...Ch. 5 - Prob. 5.96EPCh. 5 - Prob. 5.97EPCh. 5 - Prob. 5.98EPCh. 5 - Prob. 5.99EPCh. 5 - Prob. 5.100EPCh. 5 - Prob. 5.101EPCh. 5 - How many carbon atoms are present in a molecule of...Ch. 5 - Prob. 5.103EPCh. 5 - Prob. 5.104EPCh. 5 - Prob. 5.105EPCh. 5 - Prob. 5.106EPCh. 5 - Prob. 5.107EPCh. 5 - Prob. 5.108EPCh. 5 - Prob. 5.109EPCh. 5 - Prob. 5.110EPCh. 5 - Prob. 5.111EPCh. 5 - Prob. 5.112EPCh. 5 - Prob. 5.113EPCh. 5 - Prob. 5.114EPCh. 5 - Prob. 5.115EPCh. 5 - Prob. 5.116EPCh. 5 - Prob. 5.117EPCh. 5 - Prob. 5.118EPCh. 5 - Prob. 5.119EPCh. 5 - Prob. 5.120EPCh. 5 - Prob. 5.121EPCh. 5 - Prob. 5.122EPCh. 5 - Prob. 5.123EPCh. 5 - Prob. 5.124EPCh. 5 - Write the structural formulas of the reaction...Ch. 5 - Prob. 5.126EPCh. 5 - Prob. 5.127EPCh. 5 - Prob. 5.128EPCh. 5 - Prob. 5.129EPCh. 5 - Prob. 5.130EPCh. 5 - Prob. 5.131EPCh. 5 - Prob. 5.132EPCh. 5 - Prob. 5.133EPCh. 5 - Prob. 5.134EPCh. 5 - Prob. 5.135EPCh. 5 - Prob. 5.136EPCh. 5 - Prob. 5.137EPCh. 5 - Prob. 5.138EPCh. 5 - Prob. 5.139EPCh. 5 - Prob. 5.140EPCh. 5 - Prob. 5.141EPCh. 5 - Prob. 5.142EPCh. 5 - Prob. 5.143EPCh. 5 - Prob. 5.144EPCh. 5 - Prob. 5.145EPCh. 5 - Prob. 5.146EPCh. 5 - Prob. 5.147EPCh. 5 - Prob. 5.148EPCh. 5 - Draw a condensed structural formula for the...Ch. 5 - Draw a condensed structural formula for the...Ch. 5 - Prob. 5.151EPCh. 5 - Prob. 5.152EPCh. 5 - Prob. 5.153EPCh. 5 - Prob. 5.154EPCh. 5 - Prob. 5.155EPCh. 5 - Prob. 5.156EPCh. 5 - Prob. 5.157EPCh. 5 - Prob. 5.158EPCh. 5 - Prob. 5.159EPCh. 5 - Prob. 5.160EPCh. 5 - Prob. 5.161EPCh. 5 - Prob. 5.162EPCh. 5 - Prob. 5.163EPCh. 5 - Prob. 5.164EP
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Lipids - Fatty Acids, Triglycerides, Phospholipids, Terpenes, Waxes, Eicosanoids; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=7dmoH5dAvpY;License: Standard YouTube License, CC-BY