(a)
Interpretation:
Chemical equation for the conversion of given
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(a)

Explanation of Solution
Given carboxylic acid salt is sodium butanoate. The structure of sodium butanoate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
(b)
Interpretation:
Chemical equation for the conversion of given carboxylic acid salt to its parent carboxylic acid using
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(b)

Explanation of Solution
Given carboxylic acid salt is potassium oxalate. The structure of potassium oxalate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
(c)
Interpretation:
Chemical equation for the conversion of given carboxylic acid salt to its parent carboxylic acid using
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(c)

Explanation of Solution
Given carboxylic acid salt is calcium malonate. The structure of calcium malonate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
(d)
Interpretation:
Chemical equation for the conversion of given carboxylic acid salt to its parent carboxylic acid using
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(d)

Explanation of Solution
Given carboxylic acid salt is sodium benzoate. The structure of sodium benzoate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
Want to see more full solutions like this?
Chapter 5 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Steps and explanation please. Add how to solve or target similar problems.arrow_forwardWould the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.arrow_forwardThis organic molecule is dissolved in an acidic aqueous solution: OH OH A short time later sensitive infrared spectroscopy reveals the presence of a new C = O stretch absorption. That is, there must now be a new molecule present with at least one C = O bond. In the drawing area below, show the detailed mechanism that could convert the molecule above into the new molecule. Videos 849 Explanation Check C Click and drag to start dwing a structure. # 3 MAR 23 Add/Remove steparrow_forward||| 7:47 ull 57% ← Problem 19 of 48 Submit Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the product of this carbocation rearrangement. Include all lone pairs and charges as appropriate. H 1,2-alkyl shift +arrow_forwardWould the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.arrow_forwardBelow is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide (OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero formal charges. In the third box, draw the two enantiomeric products that will be produced. 5th attempt Please draw all four bonds at chiral centers. Draw the two enantiomeric products that will be produced. Draw in any hydrogen at chiral centers. 1000 4th attempt Feedback Please draw all four bonds at chiral centers. 8. R5 HO: See Periodic Table See Hint H Cl Br Jid See Periodic Table See Hintarrow_forwardShow that a molecule with configuration π4 has a cylindrically symmetric electron distribution. Hint: Let the π orbitals be equal to xf and yf, where f is a function that depends only on the distance from the internuclear axis.arrow_forward(a) Verify that the lattice energies of the alkali metal iodides are inversely proportional to the distances between the ions in MI (M = alkali metal) by plotting the lattice energies given below against the internuclear distances dMI. Is the correlation good? Would a better fit be obtained by plotting the lattice energies as a function of (1 — d*/d)/d, as theoretically suggested, with d* = 34.5 pm? You must use a standard graphing program to plot the graph. It generates an equation for the line and calculates a correlation coefficient. (b) From the graph obtained in (a), estimate the lattice energy of silver iodide. (c) Compare the results of (b) with the experimental value of 886 kJ/mol. If they do not agree, explain the deviation.arrow_forwardCan I please get help with #3 & 4? Thanks you so much!arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning




