Concept explainers
(a)
Interpretation:
Physical state at room temperature for unbranched saturated monocarboxylic acid that contains three carbon atoms has to be indicated.
Concept Introduction:
Physical property of
(b)
Interpretation:
Physical state at room temperature for unbranched saturated dicarboxylic acid that contains three carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
(c)
Interpretation:
Physical state at room temperature for unbranched saturated monocarboxylic acid that contains six carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
(d)
Interpretation:
Physical state at room temperature for unbranched saturated dicarboxylic acid that contains five carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
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Chapter 5 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Classify each molecule as optically active or inactive. Determine the configuration at each H соон Chirality center OH 애 He OH H3C Ноос H H COOH A K B.arrow_forwardQ1: Rank the relative nucleophilicity of the following species in ethanol. CH3O¯, CH3OH, CH3COO, CH3COOH, CH3S Q2: Group these solvents into either protic solvents or aprotic solvents. Acetonitrile (CH3CN), H₂O, Acetic acid (CH3COOH), Acetone (CH3COCH3), CH3CH2OH, DMSO (CH3SOCH3), DMF (HCON(CH3)2), CH3OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- 10. The main product of the following reaction is [1.1:4',1"-terphenyl]-2'-yl(1h-pyrazol-4- yl)methanone Ph N-H Pharrow_forwardDraw the Fischer projection for a D-aldo-pentose. (aldehyde pentose). How many total stereoisomers are there? Name the sugar you drew. Draw the Fischer projection for a L-keto-hexose. (ketone pentose). How many total stereoisomers are there? Draw the enantiomer.arrow_forwardDraw a structure using wedges and dashes for the following compound: H- Et OH HO- H H- Me OHarrow_forward
- Which of the following molecules are NOT typical carbohydrates? For the molecules that are carbohydrates, label them as an aldose or ketose. HO Он ОН ОН Он ОН но ΤΗ HO ОН HO eve Он он ОН ОН ОН If polyethylene has an average molecular weight of 25,000 g/mol, how many repeat units are present?arrow_forwardDraw the a-anomer cyclized pyranose Haworth projection of the below hexose. Circle the anomeric carbons. Number the carbons on the Fischer and Haworth projections. Assign R and S for each chiral center. HO CHO -H HO -H H- -OH H -OH CH₂OH Draw the ẞ-anomer cyclized furanose Haworth projection for the below hexose. Circle the anomeric carbons. Number the carbons on the Fischer and Haworth projections. HO CHO -H H -OH HO -H H -OH CH₂OHarrow_forwardName the below disaccharide. Circle any hemiacetals. Identify the numbering of glycosidic linkage, and identify it as a or ẞ. OH HO HO OH HO HO HO OHarrow_forward
- What are the monomers used to make the following polymers? F. а. b. с. d. Вецер хочому なarrow_forward1. Propose a reasonable mechanism for the following transformation. I'm looking for curved mechanistic arrows and appropriate formal charges on intermediates. OMe MeO OMe Me2N NMe2 OTBS OH xylenes OMe 'OTBSarrow_forwardWhat is the polymer made from the following monomers? What type of polymerization is used for each? а. ОН H2N но b. ن -NH2 d. H₂N NH2 довarrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
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