
Concept explainers
(a)
Interpretation:
Physical state at room temperature for unbranched saturated monocarboxylic acid that contains three carbon atoms has to be indicated.
Concept Introduction:
Physical property of
(b)
Interpretation:
Physical state at room temperature for unbranched saturated dicarboxylic acid that contains three carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
(c)
Interpretation:
Physical state at room temperature for unbranched saturated monocarboxylic acid that contains six carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.
(d)
Interpretation:
Physical state at room temperature for unbranched saturated dicarboxylic acid that contains five carbon atoms has to be indicated.
Concept Introduction:
Physical property of carboxylic acid is decided by the carbon chain and the functional group. Carboxylic acids are highly polar, as the carboxyl group is more polar. Due to this polar nature, the melting and boiling point are very high. Monocarboxylic acids that are unsubstituted which contains up to nine carbon atoms are present in liquid state. They have very sharp odor. Monocarboxylic acids that have more than ten carbon atoms in an unbranched fashion are waxy solids. They do not have any odor because of low volatility. Similar to this, dicarboxylic acids and aromatic carboxylic acids do not have any odor and they are solids.

Want to see the full answer?
Check out a sample textbook solution
Chapter 5 Solutions
Organic And Biological Chemistry
- The statements in the tables below are about two different chemical equilibria. The symbols have their usual meaning, for example AG stands for the standard Gibbs free energy of reaction and K stands for the equilibrium constant. In each table, there may be one statement that is faise because it contradicts the other three statements. If you find a false statement, check the box next to t Otherwise, check the "no false statements" box under the table. statement false? AG"1 no false statements: statement false? AG-0 0 InK-0 0 K-1 0 AH-TAS no false statements 2arrow_forwardComplete the following esterification reactions by drawing the line formulas of the carboxylic acid and alcohol required to form the ester shown. catalyst catalyst catalyst apricot fragrancearrow_forwardShow the saponification products of the following ester: You don't need to draw in the Na+ cation. catalyst, A catalyst, A catalyst, Aarrow_forward
- What would happen if the carboxylic acid and alcohol groups were on the same molecule? In essence, the molecule reacts with itself. Draw the structure of the products formed in this manner using the reactants below. If two functional groups interact with one another on the same molecule, this is called an “intramolecular" (within one) rather than "intermolecular" (between two or more) attack. OH OH catalyst OH HO catalyst catalyst HO OHarrow_forwardQ3: Write in the starting alkyl bromide used to form the following products. Include any reactants, reagents, and solvents over the reaction arrow. If more than one step is required, denote separate steps by using 1), 2), 3), etc. H OH racemic OH OH 5 racemicarrow_forwardDraw the Lewis structure of the SO3-O(CH3)2 complex shown in the bottom right of slide 2in lecture 3-3 (“Me” means a CH3 group) – include all valence electron pairs and formal charges.From this structure, should the complex be a stable molecule? Explain.arrow_forward
- please add appropriate arrows, and tell me clearly where to add arrows, or draw itarrow_forwardWhat I Have Learned Directions: Given the following reaction and the stress applied in each reaction, answer the question below. A. H2(g) + Cl2(g) 2 HCl(g) Stress applied: Decreasing the pressure 1. What is the Keq expression? 2. What will be the effect in the number of moles of HCl(g)? 3. What will be the Equilibrium Shift or the reaction? B. Fe3O4(s) + 4 H2(g) + heat 53 Fe(s) + 4 H₂O(g) Stress applied: Increasing the temperature 1. What is the Keq expression?. 2. What will be the effect in the volume of water vapor collected? 3. What will be the Equilibrium Shift or the reaction? C. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) + heat Stress applied: Increasing the volume of the container 1. What is the Keq expression?. 2. What will be the effect in the amount of H₂O? 3. What will be the Equilibrium Shift or the reaction?arrow_forwardConsider the solubility products (Ksp values) for the following compounds:SrSO4 (Ksp = 7.6 x 10−7), BaSO4 (Ksp = 1.5 x 10−9), SrCO3 (Ksp = 7.0 x 10−10), BaCO3 (Ksp = 1.6 x 10−9)Which anion is the harder base, CO32− or SO42−? Justify your answer.arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning





