
Interpretation: From the given pairs, the pair whose atomic size cannot be compared using the periodic table should be determined.
Concept Introduction:
Periodic Table: The available chemical elements are arranged considering their
In periodic table the horizontal rows are called periods and the vertical column are called group.
There are seven periods and 18 groups present in the table and some of those groups are given special name as follows,
Atomic Number: Atomic number of the element is equal to the number of protons present in the nucleus of the element which is denoted by symbol Z. The superscript presents on the left side of the
Atomic radius: Atomic radius is the distance between the atomic nucleus and outermost electron of an atom. From the atomic radius, the size of atoms can be visualized. But there is no specific distance from nucleus to electron due to electron cloud around the atom does not have well-defined boundary.
The atomic radius follows the specific trend in the periodic table that it gets decreases as we go from left to right of the period due to increased nuclear charge the electrons gets added to the same sub-shell strongly binds resulting to decrease in the size.
It increases as we move from top to bottom of the table due to addition of shell in the element.
To match: The given ions with the given spheres according to their relative sizes.

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Chapter 4 Solutions
Chemistry: Atoms First V1
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- Predict the intermediate 1 and final product 2 of this organic reaction: NaOMe ག1, ད།་, - + H You can draw 1 and 2 in any arrangement you like. 2 work up Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Parrow_forwardWhat is the total energy cost associated with the compound below adopting the shown conformation? CH3 HH DH CH3arrow_forwardΗΝ, Draw Final Product C cyclohexanone pH 4-5 Edit Enamine H3O+ CH3CH2Br THF, reflux H Edit Iminium Ionarrow_forward
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- H H:O::::H H H HH H::O:D:D:H HH HH H:O:D:D:H .. HH H:O:D:D:H H H Select the correct Lewis dot structure for the following compound: CH3CH2OHarrow_forwardRank the following compounds in order of decreasing boiling point. ннннн -С-С-Н . н-с- ННННН H ΗΤΗ НННН TTTĪ н-с-с-с-с-о-н НННН НН C' Н н-с-с-с-с-н НН || Ш НННН H-C-C-C-C-N-H ННННН IVarrow_forwardRank the following compounds in order of decreasing dipole moment. |>||>||| ||>|||>| |>|||>|| |||>||>| O ||>>||| H F H F H c=c || H c=c F F IIIarrow_forward
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