Prescott's Microbiology
10th Edition
ISBN: 9781259281594
Author: Joanne Willey, Linda Sherwood Adjunt Professor Lecturer, Christopher J. Woolverton Professor
Publisher: McGraw-Hill Education
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Chapter 34.7, Problem 3.1RIA
Summary Introduction
Immunoglobulins (Ig) or antibodies are glycoproteins that are produced by plasma B cells. They play a major role in the immune system. They are specific in recognizing and binding to the antigen. There are five classes of immunoglobulins, such as IgG, IgA, IgM, IgD, and IgE.
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In a particular species, the gene for the kappa light chain has 200 V segments and 4 J segments. In the gene for the lambda light chain, this species has 300 V segments and 6 J segments. If only the antibody diversity arising from somatic recombination is taken into consideration, how many different types of light chains are possible?
The immunoglobulin molecules of a particular mammalian species have kappa and lambda light chains and heavy chains. The kappa gene consists of 250 V and 8 J segments. The lambda gene contains 200 V and 4 J segments. The gene for the heavy chain consists of 300 V, 8 J, and 4 D segments. If just somatic recombination and random combinations of light and heavy chains are taken into consideration, how many different types of antibodies can be produced by this species?
If the heavy chain of an antibody is approximately 450 amino acids long, how much DNA would be required to encode 10° separate heavy chain genes?
Chapter 34 Solutions
Prescott's Microbiology
Ch. 34.2 - What does the term valence mean and how does an...Ch. 34.2 - Distinguish between self and nonself substances.Ch. 34.2 - Prob. 2RIACh. 34.2 - How does a hapten differ from an antigen?Ch. 34.3 - What are the types of adaptive immunity?Ch. 34.3 - What distinguishes natural from artificial...Ch. 34.3 - What are ways that active immunity is different...Ch. 34.3 - Of the four types of acquired immunity, which do...Ch. 34.4 - On what types of cells are MHC class I molecules...Ch. 34.4 - Prob. 2MI
Ch. 34.4 - What are MHCs and HLAs? Describe the roles of the...Ch. 34.4 - Prob. 2RIACh. 34.4 - Prob. 3RIACh. 34.4 - How are foreign peptides processed so as to...Ch. 34.5 - Prob. 1MICh. 34.5 - Prob. 1RIACh. 34.5 - Prob. 2RIACh. 34.5 - Describe antigen processing. How does this process...Ch. 34.5 - Prob. 4RIACh. 34.5 - Prob. 5RIACh. 34.5 - Prob. 6RIACh. 34.6 - Which cells are functioning as APCs in this...Ch. 34.6 - Prob. 1RIACh. 34.6 - Briefly compare and contrast B cells and T cells...Ch. 34.6 - Prob. 3RIACh. 34.6 - Prob. 4RIACh. 34.7 - Prob. 1MICh. 34.7 - Prob. 2MICh. 34.7 - Prob. 3MICh. 34.7 - Prob. 1.1RIACh. 34.7 - Prob. 1.2RIACh. 34.7 - Prob. 1.3RIACh. 34.7 - Prob. 1.4RIACh. 34.7 - Prob. 2.1RIACh. 34.7 - Prob. 2.2RIACh. 34.7 - Prob. 2.3RIACh. 34.7 - Prob. 2.4RIACh. 34.7 - Prob. 2.5RIACh. 34.7 - Prob. 3.1RIACh. 34.7 - Prob. 3.2RIACh. 34.7 - In addition to combinatorial joining, what other...Ch. 34.8 - What is the difference between a precipitation and...Ch. 34.8 - Prob. 1RIACh. 34.8 - Prob. 2RIACh. 34.8 - How does opsonization inhibit microbial adherence...Ch. 34.8 - Prob. 4RIACh. 34.9 - Prob. 1RIACh. 34.9 - How would you define anergy?Ch. 34.10 - Prob. 1MICh. 34.10 - Prob. 2MICh. 34.10 - Prob. 1.1RIACh. 34.10 - Prob. 1.2RIACh. 34.10 - Prob. 1.3RIACh. 34.10 - Prob. 1.4RIACh. 34.10 - Prob. 1.5RIACh. 34.10 - What is an autoimmune disease and how might it...Ch. 34.10 - Prob. 2.2RIACh. 34.10 - Prob. 2.3RIACh. 34.10 - Prob. 2.4RIACh. 34 - What properties of proteins make them suitable...Ch. 34 - What other biotechnologies could be invented based...Ch. 34 - Speculate as to how MHC, TCR, and BCR molecules...Ch. 34 - Prob. 4CHICh. 34 - Prob. 5CHICh. 34 - In an effort to better understand the mechanisms...Ch. 34 - Prob. 7CHI
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- Antibodies are effective against bacteria as well as viruses, but some bacteria produce an enzyme that cuts immunoglobulin G molecules right at the “bend” to separate each antigen-binding “arm” from the “stem.” (a) What type of bond is broken by the bacterial enzyme and what type of reaction does this enzyme catalyze? (b) Would the action of the bacterial enzyme affect the ability of immunoglobulins to cross-link bacterial cells?.arrow_forwardWhen a mixture of different IgG antibody proteins are treated with the enzyme papain, each antibody is cleaved into three roughly equal size fragments. From each original antibody, two of the three fragments are identical to each other, and represent the ‘arms’ of the antibody ‘Y’. These fragments are known as Fab fragments. The third fragment is known as the Fc region, because this fragment will crystallize when purified. The reason a mixture of Fc fragments will crystallize is because: It is the only part of the antibody protein that can easily be purified at the high concentrations needed for crystallization. It has no disulfide bonds holding the domains together, as disulfide bonds will inhibit crystallization. It is the only fragment of the antibody that still has disulfide bonds, so it remains intact during the crystallization process. The Fc fragments of IgG are much more water soluble than the Fab fragments. All Fc fragments generated from a mixture of IgG molecules have the…arrow_forwardMost of the enzymes involved in immunoglobulin gene rearrangement are ubiquitously expressed in all cells of the body. However, the specific recombination events between V, J, and D gene segments that generate antibody diversity occur only in developing B cells. How do RAG-1 and RAG-2 ensure that recombination takes place at antibody gene segments?arrow_forward
- Each immunoglobulin (Ig) domain is composed of a structure known as a ‘b-sandwich,’ which consists of two b sheets covalently linked by a disulfide bond. Only a subset of the ~110 amino acids in each domain are required to establish this overall structure, and it is these amino acids that are highly conserved when comparing Ig domains to each other. What might be the advantage of this structure for use as antibody variable domains?arrow_forwardAntibody diversity is generated by multiple mechanisms, each of which contributes to the generation of antibodies with up to 1011 different amino acid sequences in their antigen-binding sites. Several of these mechanisms involve changes in the DNA sequences encoding the antibody heavy and light chain proteins. One mechanism that does not rely on changes to the DNA within the immunoglobulin heavy and light chain gene loci is, instead, dependent on: The contributions of amino acids from both the heavy chain and the light chain to form the antigen-binding site The random usage of V, D, and J gene segments to form the heavy chain V region sequence The random usage of k light chains versus l light chains to pair with the heavy chain The activity of TdT to add random nucleotides at the junctions between the V, J, and D region sequences The fact that heavy chain V regions contain an extra gene segment encoded by the D region compared to light chain V regionsarrow_forwardFor an Immunoprecipitation experiment: What is the function of the IP-2 tube in this experiment?arrow_forward
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