Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 29.SE, Problem 48AP
Interpretation Introduction
Interpretation:
To explain how the 3-phosphoglyceryl phosphate and phosphoenolpyruvate transfer a phosphate group to ADP while glucose 6-phosphate.
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Oxaloacetate + ADP + Pi + H+ ---> Pyruvate + ATP + HCO3- ΔGo’ = 13.91 kJ/mol
Lactate + NAD+ ---> Pyruvate + NADH + H+ ΔGo’ = 25.12 kJ/mol
Oxaloacetate + GTP ---> Phosphoenolpyruvate + GDP + CO2 ΔGo’ = -28.40 kJ/mol
HCO3- + H+ ---> CO2 + H2O ΔGo’ = -41.45 kJ/mol
GDP + ATP ---> GTP + ADP ΔGo’ = -0.003 kJ/mol
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Lactate + NAD+ + 2ATP + H2O ---> Phosphoenolpyruvate + NADH + 2ADP + Pi + 3H+
From the above information, calculate theΔGo’ for the overall reaction shown…
Oxaloacetate + ADP + Pi + H+ ---> Pyruvate + ATP + HCO3- ΔGo’ = 13.91 kJ/mol
Lactate + NAD+ ---> Pyruvate + NADH + H+ ΔGo’ = 25.12 kJ/mol
Oxaloacetate + GTP ---> Phosphoenolpyruvate + GDP + CO2 ΔGo’ = -28.40 kJ/mol
HCO3- + H+ ---> CO2 + H2O ΔGo’ = -41.45 kJ/mol
GDP + ATP ---> GTP + ADP ΔGo’ = -0.003 kJ/mol
_________________________________________________________________________________________________________________
Lactate + NAD+ + 2ATP + H2O ---> Phosphoenolpyruvate + NADH + 2ADP + Pi + 3H+
From the above information, calculate the Keq’ for the overall reaction shown…
Which yields more energy upon hydrolysis, ATP or glycerol 1-phosphate? Why?
Chapter 29 Solutions
Organic Chemistry
Ch. 29.1 - Prob. 1PCh. 29.3 - Write the equations for the remaining passages of...Ch. 29.3 - Prob. 3PCh. 29.4 - Write a mechanism for the dehydration reaction of...Ch. 29.4 - Evidence for the role of acetate in fatty-acid...Ch. 29.4 - Does the reduction of acetoacetyl ACP in step 6...Ch. 29.5 - Prob. 7PCh. 29.5 - Look at the entire glycolysis pathway, and make a...Ch. 29.6 - Prob. 9PCh. 29.7 - Prob. 10P
Ch. 29.7 - Write mechanisms for step 2 of the citric acid...Ch. 29.7 - Prob. 12PCh. 29.8 - Prob. 13PCh. 29.9 - Write all the steps in the transamination reaction...Ch. 29.9 - What -keto acid is formed on transamination of...Ch. 29.9 - Prob. 16PCh. 29.SE - Prob. 17VCCh. 29.SE - Identify the following intermediate in the citric...Ch. 29.SE - The following compound is an intermediate in the...Ch. 29.SE - Prob. 20VCCh. 29.SE - In the pentose phosphate pathway for degrading...Ch. 29.SE - Prob. 22MPCh. 29.SE - One of the steps in the pentose phosphate pathway...Ch. 29.SE - One of the steps in the pentose phosphate pathway...Ch. 29.SE - Prob. 25MPCh. 29.SE - Prob. 26MPCh. 29.SE - Prob. 27MPCh. 29.SE - Prob. 28MPCh. 29.SE - Prob. 29MPCh. 29.SE - Prob. 30MPCh. 29.SE - Prob. 31MPCh. 29.SE - Prob. 32APCh. 29.SE - Prob. 33APCh. 29.SE - Prob. 34APCh. 29.SE - Prob. 35APCh. 29.SE - Prob. 36APCh. 29.SE - Prob. 37APCh. 29.SE - Prob. 38APCh. 29.SE - Prob. 39APCh. 29.SE - Prob. 40APCh. 29.SE - Prob. 41APCh. 29.SE - Prob. 42APCh. 29.SE - Prob. 43APCh. 29.SE - Prob. 44APCh. 29.SE - Prob. 45APCh. 29.SE - Prob. 46APCh. 29.SE - Prob. 47APCh. 29.SE - Prob. 48APCh. 29.SE - Prob. 49APCh. 29.SE - Prob. 50APCh. 29.SE - In glycerol metabolism, the oxidation of...Ch. 29.SE - Prob. 52APCh. 29.SE - Prob. 53APCh. 29.SE - Prob. 54APCh. 29.SE - In step 7 of fatty-acid biosynthesis (Figure...Ch. 29.SE - Prob. 56AP
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- The first step of the metabolic process known as glycolysis is the conversion of glucose to glucose- 6-phosphate. This process has a positive value for rG' Glucose + Pi Glucose-6-phosphate + H2O rG' = +13.8 kJ/mol-rxn This reaction is coupled to the hydrolysis of ATP ATP + H2O ADP + Pi rG' = -30.5 kJ/mol-rxn What is the sum of these two equations and the value of rG' for the coupled reaction? Is the coupled reaction product-favored at equilibrium?arrow_forwardCan a chemical that, in essence, goes through the body unchanged be an essential nutrient? Explain.arrow_forwardBelow is the overall net equation for the complete oxidation of pyruvate. Calculate the number of ATP molecules that can be produced from the complete oxidation of 6 molecules of pyruvate. Pyruvate + 4NAD+ + FAD + GDP + Pi + 2H₂O → 3CO2 + 4NADH + 4H+ + FADH2 + GTP (Given: The oxidation of one NADH yields 2.5 ATP; the oxidation of one FADH2 yields 1.5 ATP; and one GDP yields 1 ATP.) O 75 ATP O 60 ATP O 12.5 ATP O 32 ATParrow_forward
- NADH and FADH2 can "create" ATP only if the cell can do electron transport True Falsearrow_forwardNeed help with 5arrow_forwardRefer to the following reaction. The substrate of this reaction is called through a mechanism called "Feed Forward Activation". (A) Phosphoenolpyruvate, Fructose 1,6-bisphosphate Lactate, NADH OPO₂²- ADP ATP J = 4 O H₂C H₂C 2-phosphoglycerate, AMP Glyceraldehyde 3-phosphate, ATP and the enzyme is activated by high conc. ofarrow_forward
- The image below shows the reactions of the citric acid cycle. Label the reaction types on the diagram. COO CH-OH CH₂ COO 8-5-9-8 HC H₂O NADH +H+ NAD+- FADH2 "7 FAD COO C=O CH₂ COO™ COO CH3-C-COA + H₂O acetyl-CoA COA COO™ Ī CH₂ HỌ—C—COO CH₂ COO™ COO HO-C-H COO™ COO™ CH₂ CH-COO NAD+ NAD+ + COA Attempt 2 NADH + H+ + CO2 NADH + H+ + CO2 COO™ CH₂ CH₂ C=O COO™arrow_forwardThe enzyme that catalyzes reaction below can be classified as: NAD* NADH + H* Но- H-Ć- Н—с—н H- malate dehydrogenase Oxaloacetate Malatearrow_forwardThe rate-limiting step is a metabolic pathway is the slowest step which determines the overall rate of the other reactions in the pathway. In glycolysis, the rate limiting step is a phosphorylation reaction where phosphofructokinase (PFK-1) catalyzes the reaction fructose-6-bisphosphate -> fructose-1,6-bisphosphate, the same step in gluconeogenesis. Select one: The statement is FALSE. The statement is TRUE.arrow_forward
- The average adult consumes approximately 11,700 kJ per day. Assuming that the metabolic pathways leading to ATP synthesis operate at 50% thermodynamic efficiency, about 5850 kJ ends up in the form of synthesized ATP. The average adult consumes approximately 11,700 kJ per day. Assuming that the metabolic pathways leading to ATP synthesis operate at 50% thermodynamic efficiency, about 5850 kJ ends up in the form of synthesized ATP. Imagine that creatine phosphate, rather than ATP, is the universal energy carrier molecule in the human body. Assume that the cellular concentrations of creatine phosphate, creatine, and phosphate are 21.7 mM, 2.17×10-3 mM, and 6.30 mM, respectively. Calculate the weight of creatine phosphate that would need to be consumed each day by a typical adult human if creatine phosphate could not be recycled. Estimate the free energy of hyrdolysis of creatine phosphate under cellular conditions to determine how many moles are required. Use the standard…arrow_forwardTrypanosomes living in the bloodstream obtain all their free energy from glycolysis. They take up glucose from the host’s blood and excrete pyruvate as a waste product. In this part of their life cycle, trypanosomes do not carry out any oxidative phosphorylation, but they do use another oxygen-dependent pathway, which is absent in mammals, to oxidize NADH. Would this pathway be necessary if the trypanosome excreted lactate rather than pyruvate? Explain.arrow_forwardHow many moles of ATP are obtained from the catabolism of 5g of a triglyceride made of a C16 fatty acid, a C17 fatty acid, and a C24 fatty acid. Use the following molecular mass values for your calculations. H=1g/mol, C=12g/mol, O=16g/molarrow_forward
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