
In Problems 39-62, graph each function using the techniques of shifting, compressing, stretching, and/or reflecting. Stan with the graph of the basic function (for example, ) and show all stages. Be sure to show at least three key points. Find the domain and the range of each function.

To graph: The function , using the techniques of shifting, compressing, stretching, and/or reflecting. Start with the graph of the basic function (for example, ) and show all stages. Be sure to show at least three key points. Find the domain and the range of each function.
Answer to Problem 44AYU
Domain of the function is .
Range of the function is .
Explanation of Solution
Given:
Graph:
Now use the following steps to obtain the graph of .
Step 1: The function is the square root function.
square root function
Step 2: To obtain the graph of , replace by from each on the graph of , that it is shifted left 1 unit.
replace by ; Horizontal shift left 1 unit.
Interpretation:
Domain of the function is .
Range of the function is .
Chapter 2 Solutions
Precalculus Enhanced with Graphing Utilities
Additional Math Textbook Solutions
Introductory Statistics
College Algebra with Modeling & Visualization (5th Edition)
University Calculus: Early Transcendentals (4th Edition)
Basic Business Statistics, Student Value Edition
Elementary Statistics
Elementary Statistics: Picturing the World (7th Edition)
- Solve please thanks!arrow_forwardSolve please and thank youarrow_forwardAccording to Newton's law of universal gravitation, the force F between two bodies of constant mass GmM m and M is given by the formula F = , where G is the gravitational constant and d is the d² distance between the bodies. a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to distance d. F' (d) 2GmM b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation, rounding to 2 decimal places. -6.67x10 N/m syntax incomplete.arrow_forward
- Solve please and thank youarrow_forwardmv2 The centripetal force of an object of mass m is given by F (r) = rotation and r is the distance from the center of rotation. ' where v is the speed of r a. Find the rate of change of centripetal force with respect to the distance from the center of rotation. F(r) b. Find the rate of change of centripetal force of an object with mass 500 kilograms, velocity of 13.86 m/s, and a distance from the center of rotation of 300 meters. Round to 2 decimal places. N/m (or kg/s²) F' (300)arrow_forwardSolve work shown please and thanks!arrow_forward
- Given the following graph of the function y = f(x) and n = = 6, answer the following questions about the area under the curve from x graph to enlarge it.) 1 (Round your answer to within two decimal places if necessary, but do not round until your final computation.) a. Use the Trapezoidal Rule to estimate the area. Estimate: T6 G b. Use Simpson's Rule to estimate the area. Estimate: S6 - ID = 0 to x = 6. (Click on aarrow_forward"Solve the following differential equation using the Operator Method and the Determinant Method:" Solve by dr no ai """'+3y"" + 3y+y=arrow_forward(4,4) M -4 2 2 -4 (-4,-4) 4 8 10 12 (8,-4) (12,-4) Graph of f The figure shows the graph of a piecewise-linear function f. For −4≤x≤12, the function g is x defined by g(x) = √ƒ (t)dt . . Find the value of g(6). Find the value of g'(6). |arrow_forward
- PREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE ANOTHER Find the derivative of the function. f'(x) = X x + √3x f(x) = 3x-5 (3√√3x+11√√x+5√3 2√√x (3x-5)² Need Help? Read It SUBMIT ANSWERarrow_forwardPREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE A Find the derivative of the function and evaluate f'(x) at the given val f(x) = (√√√x + 3x) (x3/2 - x); x = 1 f'(x) = 9x 412 (12x (13) 2 - 4x-3√√√x f'(1) = 2 Need Help? Read It Watch It SUBMIT ANSWERarrow_forwardConsider the following functions. g(x) = x + √3x h(x) = 3x-5 x + √3x f(x) = = 3x-5 Find the derivative of each function. g'(x) h'(x) = = f'(x) = 3 = +1 2√3x 3 (3√3x + 10√√x +5√√√3 2√√x (3x-5)² Need Help? Read It SUBMIT ANSWERarrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





