Chapter 2.5, Problem 96AYU

To determine

To find: The area under the curve of $y=\sqrt{-x}$ bounded below the x -axis and on the left by $x=-4$ .

Explanation of Solution

Given: The area under the curve $y=\sqrt{x}$ bounded below by the x -axis and on the right by $x=4$ is $\frac{16}{3}$ square units.

First draw the figure of given curve on same screen.

  

The area under the curve $y=\sqrt{x}$ bounded below by the x -axis and on the right by $x=4$ is $\frac{16}{3}$ square units.

According to graph, Left side area is symmetrical about right side.

The area under the curve of $y=\sqrt{-x}$ bounded below the x -axis and on the left by $x=-4$ would be same as $\frac{16}{3}$ square units.

This is because area is positive quantity. If symmetry in figure then it might be same.