Concept explainers
To find: The pair of function from the provided functions.
Answer to Problem 14RE
Solution:
a. The domain of the pair is .
b. The domain of the pair is .
c. The domain of the pair is .
d. The domain of the pair is .
Explanation of Solution
Given:
It is provided in the problem that the function and .
Formula used:
A
The domain of a function is the set of all real values of that will give real values for . The range of a function is the set of all real values of that you can get by plugging real numbers into .
Calculation:
a. For , . The function says to divide by . Since division by 0 is not defined, the denominator can never be 0, so can never equal 0 or 1. The domain of the pair is .
b. For , . The function says to divide by . Since division by 0 is not defined, the denominator can never be 0, so can never equal 0 or 1. The domain of the pair is .
c. For . The function says to divide by . Since division by 0 is not defined, the denominator can never be 0, so can never equal 0 or 1. The domain of the pair is .
d. For , . The function says to divide by . Since division by 0 is not defined, the denominator can never be 0, so can never equal 1. The domain of the pair is .
Chapter 2 Solutions
Precalculus Enhanced with Graphing Utilities
Additional Math Textbook Solutions
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (4th Edition)
Glencoe Math Accelerated, Student Edition
Calculus and Its Applications (11th Edition)
Calculus: Early Transcendentals (2nd Edition)
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