ORGANIC CHEMISTRY-PRINT MULTI TERM
4th Edition
ISBN: 9781119832614
Author: Klein
Publisher: WILEY
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Question
Chapter 22.4, Problem 11CC
Interpretation Introduction
Interpretation: The given compound that can’t be prepared from an
Concept Introduction:
When sodium cyanide is allowed to react with alkyl halide, halide group is replaced by cyanide group via SN2 nucleophilic substitution reaction. The cyanide group on treatment with lithium aluminum hydride which is a strong reducing agent followed by water work-up, it reduces the cyanide group into methylene primary amine. There is a single carbon skeleton increment in the given compound through this process.
The carboxylic acid is converted into the corresponding chloride using thionyl chloride which is allowed to react with ammonia giving the corresponding amide. The amide group on treatment with lithium aluminum hydride which is a strong reducing agent followed by water work-up, it reduces the amide group into methylene primary amine.
To find: Explain the reason for the given compound that can’t be prepared from an alkyl halide or carboxylic acid which serves as a precursor in the preparation of the given amine
Give the general reaction for amine preparation from alkyl halide or carboxylic acid
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Complete combustion of a 0.6250 g sample of the unknown crystal with excess O2 produced 1.8546 g of CO2 and 0.5243 g of H2O. A separate analysis of a 0.8500 g sample of the blue crystal was found to produce 0.0465 g NH3. The molar mass of the substance was found to be about 310 g/mol. What is the molecular formula of the unknown crystal?
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Chapter 22 Solutions
ORGANIC CHEMISTRY-PRINT MULTI TERM
Ch. 22.2 - Prob. 1LTSCh. 22.2 - Prob. 1PTSCh. 22.2 - Prob. 2PTSCh. 22.3 - Prob. 4CCCh. 22.3 - Prob. 5CCCh. 22.3 - Prob. 6CCCh. 22.3 - Prob. 7CCCh. 22.3 - Prob. 8CCCh. 22.3 - Prob. 9CCCh. 22.4 - Prob. 10CC
Ch. 22.4 - Prob. 11CCCh. 22.5 - Prob. 2LTSCh. 22.5 - Prob. 12PTSCh. 22.6 - Prob. 3LTSCh. 22.6 - Prob. 14PTSCh. 22.8 - Prob. 20CCCh. 22.8 - Prob. 21CCCh. 22.8 - Prob. 22CCCh. 22.9 - Prob. 5LTSCh. 22.9 - Prob. 23PTSCh. 22.10 - Prob. 25CCCh. 22.11 - Prob. 26CCCh. 22.11 - Prob. 6LTSCh. 22.11 - Prob. 27PTSCh. 22 - Prob. 33PPCh. 22 - Prob. 34PPCh. 22 - Prob. 35PPCh. 22 - Prob. 36PPCh. 22 - Prob. 37PPCh. 22 - Prob. 38PPCh. 22 - Prob. 39PPCh. 22 - Prob. 40PPCh. 22 - Prob. 41PPCh. 22 - Prob. 42PPCh. 22 - Prob. 43PPCh. 22 - Prob. 44PPCh. 22 - Prob. 45PPCh. 22 - Prob. 46PPCh. 22 - Prob. 47PPCh. 22 - Prob. 48PPCh. 22 - Prob. 49PPCh. 22 - Prob. 50PPCh. 22 - Prob. 51PPCh. 22 - Prob. 52PPCh. 22 - Prob. 53PPCh. 22 - Prob. 54PPCh. 22 - Prob. 55PPCh. 22 - Prob. 56PPCh. 22 - Prob. 57PPCh. 22 - Prob. 58PPCh. 22 - Prob. 59PPCh. 22 - Prob. 60PPCh. 22 - Prob. 61PPCh. 22 - Prob. 62PPCh. 22 - Prob. 63PPCh. 22 - Prob. 64PPCh. 22 - Prob. 65PPCh. 22 - Prob. 66PPCh. 22 - Prob. 67PPCh. 22 - Prob. 68PPCh. 22 - Prob. 69PPCh. 22 - Prob. 70PPCh. 22 - Prob. 71PPCh. 22 - Prob. 80IPCh. 22 - Prob. 81IPCh. 22 - Prob. 82IPCh. 22 - Prob. 83IPCh. 22 - Prob. 84IPCh. 22 - Prob. 86IPCh. 22 - Prob. 87IPCh. 22 - Prob. 88IPCh. 22 - Prob. 89IPCh. 22 - Prob. 90IP
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