ORGANIC CHEMISTRY-PRINT MULTI TERM
ORGANIC CHEMISTRY-PRINT MULTI TERM
4th Edition
ISBN: 9781119832614
Author: Klein
Publisher: WILEY
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Chapter 22, Problem 82IP
Interpretation Introduction

Interpretation: The structure of piperazine with molecular formula C4H10N2 that exhibits two signals in its proton NMR spectrum has to be drawn.

Concept introduction:

The arrangement of atoms that are bonded together determines its constitution and molecular formula of that particular compound.  This concept is referred as structural isomers or in more modern term constitutional isomers.  Each atom has a typical valency or valence which is defined as the ability of an atom to form a chemical bond with other atoms.  For example, carbon has four valence or tetravalent that means carbon has the capacity to form four bonds with other elements or other atoms.  Nitrogen atoms are trivalent whereas hydrogen atoms are monovalent in nature.

In proton NMR, the signals are based on the arrangement of hydrogen atoms that are connected to carbon or nitrogen atoms.

To find: Draw the structure of piperazine with molecular formula C4H10N2 that exhibits two signals in its proton NMR spectrum

Find the valency for carbon (C), hydrogen (H) and nitrogen (N) in C4H10N2

ORGANIC CHEMISTRY-PRINT MULTI TERM, Chapter 22, Problem 82IP

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6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3
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Q1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identical

Chapter 22 Solutions

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