(a) Interpretation: The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned Concept introduction: Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

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Answer 1

Question

Chapter 20, Problem 65P

Interpretation Introduction

(a)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Interpretation Introduction

(b)

Interpretation:

The major disaccharide or polysaccharide that constitutes the given item in (b) should be mentioned.

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Interpretation Introduction

(c)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

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Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100

Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.

For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.

Answer 2

Question

Chapter 20, Problem 65P

Interpretation Introduction

(a)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Interpretation Introduction

(b)

Interpretation:

The major disaccharide or polysaccharide that constitutes the given item in (b) should be mentioned.

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Interpretation Introduction

(c)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

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Answer 3

Question

Chapter 20, Problem 65P

Interpretation Introduction

(a)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Interpretation Introduction

(b)

Interpretation:

The major disaccharide or polysaccharide that constitutes the given item in (b) should be mentioned.

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Interpretation Introduction

(c)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

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Answer 4

Question

Chapter 20, Problem 65P

Interpretation Introduction

(a)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Interpretation Introduction

(b)

Interpretation:

The major disaccharide or polysaccharide that constitutes the given item in (b) should be mentioned.

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Interpretation Introduction

(c)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

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Answer 5

Chapter 20, Problem 65P

Interpretation Introduction

(a)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Interpretation Introduction

(b)

Interpretation:

The major disaccharide or polysaccharide that constitutes the given item in (b) should be mentioned.

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Interpretation Introduction

(c)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Answer 6

Chapter 20, Problem 65P

Interpretation Introduction

(a)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Answer 7

Chapter 20, Problem 65P

Interpretation Introduction

(a)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The major disaccharide or polysaccharide that constitutes the given item in (b) should be mentioned.

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The major disaccharide or polysaccharide that constitutes the given item in (b) should be mentioned.

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned

Concept introduction:

Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 20.1 - Label the hemiacetal carbonthe carbon bonded to...Ch. 20.2 - Prob. 20.1PP Ch. 20.2 - Prob. 20.2P Ch. 20.2 - Prob. 20.3P Ch. 20.2 - Prob. 20.4P Ch. 20.2 - Prob. 20.5P Ch. 20.2 - Prob. 20.2PP Ch. 20.2 - Prob. 20.6P Ch. 20.2 - Prob. 20.7P Ch. 20.3 - Prob. 20.8P

(a) Interpretation: The major disaccharide or polysaccharide that constitute the given item in (a) should be mentioned Concept introduction: Polysaccharide is a chain of monosaccharides bonded together by glycosidic bonds. Disaccharide isa pair of monosaccharides bonded together by glycosidic bonds.

Solution Summary: The author explains that polysaccharide is a chain of monosuccharides bonded together by glycosidic bonds.

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Chapter 20 Solutions

Solution Summary: The author explains that polysaccharide is a chain of monosuccharides bonded together by glycosidic bonds.

Concept explainers

(c) Interpretation: The major disaccharide or polysaccharide that constitute the given item in (c) should be mentioned Concept introduction: Polysaccharide is a chain of monosaccharide bonded together by glycosidic bonds. Disaccharide is a pair of monosaccharide bonded together by glycosidic bonds.

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Chapter 20 Solutions