The three acetals in rebaudioside should be located. Concept Introduction: Addition of one molecule of alcohol to an aldehyde or ketone results in a hemiacetal. Here, the C=O double bond breaks and single bonds are formed. If the hemiacetal is acyclic, it is not stable. Acyclic hemiacetal reacts with a second alcohol molecule and forms acetal. likewise, a disaccharide or polysaccharide is formed when a hemiacetal of a one monosaccharide is reacted with a hydroxyl group of a second monosaccharide forming an acetal.

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Answer 1

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20.5, Problem 20.14P

Interpretation Introduction

Interpretation:

The three acetals in rebaudioside should be located.

Concept Introduction:

Addition of one molecule of alcohol to an aldehyde or ketone results in a hemiacetal. Here, the C=O double bond breaks and single bonds are formed. If the hemiacetal is acyclic, it is not stable. Acyclic hemiacetal reacts with a second alcohol molecule and forms acetal.

likewise, a disaccharide or polysaccharide is formed when a hemiacetal of a one monosaccharide is reacted with a hydroxyl group of a second monosaccharide forming an acetal.

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5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.

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Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20.5, Problem 20.14P

Interpretation Introduction

Interpretation:

The three acetals in rebaudioside should be located.

Concept Introduction:

Addition of one molecule of alcohol to an aldehyde or ketone results in a hemiacetal. Here, the C=O double bond breaks and single bonds are formed. If the hemiacetal is acyclic, it is not stable. Acyclic hemiacetal reacts with a second alcohol molecule and forms acetal.

likewise, a disaccharide or polysaccharide is formed when a hemiacetal of a one monosaccharide is reacted with a hydroxyl group of a second monosaccharide forming an acetal.

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Answer 3

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20.5, Problem 20.14P

Interpretation Introduction

Interpretation:

The three acetals in rebaudioside should be located.

Concept Introduction:

Addition of one molecule of alcohol to an aldehyde or ketone results in a hemiacetal. Here, the C=O double bond breaks and single bonds are formed. If the hemiacetal is acyclic, it is not stable. Acyclic hemiacetal reacts with a second alcohol molecule and forms acetal.

likewise, a disaccharide or polysaccharide is formed when a hemiacetal of a one monosaccharide is reacted with a hydroxyl group of a second monosaccharide forming an acetal.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 20.5, Problem 20.14P

Interpretation Introduction