Concept explainers
(a)
Interpretation:
The acetal and hemiacetal in sophorose needs to be labeled.
Concept Introduction:
In a hemiacetal, an alcohol and ether attached to the same carbon.
A hemiacetal with an alcohol forms an acetal.
(b)
Interpretation:
Each monosaccharide ring should be numbered.
Concept Introduction:
Monosaccharides or simple sugars are the simplest carbohydrates. Generally, have three to six carbon atoms in achain, with a carbonyl group at either the terminal carbon, numbered C1, or the carbon adjacent to it, numbered C2.
(c)
Interpretation:
Glycosidic linkage needs to be classified as a or β and its location should be designated using numbers.
Concept Introduction:
Disaccharides are carbohydrates composed of two monosaccharides.
Disaccharides are acetals, compounds that contain two alkoxy groups (OR groups) bonded to the same carbon.
A disaccharide results when a hemiacetal of one monosaccharide reacts with a hydroxyl group of a second monosaccharide to form an acetal. The new C-O bond that joins the two rings together is called a glycosidic linkage.
The two monosaccharide rings may be five-membered or six-membered. All disaccharides contain at least one acetal that joins the rings together. Each ring is numbered beginning at the anomeric carbon, the carbon in each ring bonded to two oxygen atoms
An a glycoside has the glycosidic linkage oriented down, below the plane of the ring that
contains the acetal joining the monosaccharides.
A β glycoside has the glycosidic linkage oriented up, above the plane of the ring that
contains the acetal joining the monosaccharides.
(d)
Interpretation:
Whether the hemiacetal drawn as an a or β anomer should be predicted.
Concept Introduction:
Anomers are cyclic monosaccharides or glycosides that are epimers, differing from each other in the configuration of C-1 if they are aldoses or in the configuration at C-2 if they are ketoses. The epimeric carbon in anomers are known as anomeric carbon or anomeric center.
Depending on the orientation of carbon number 1 when the carbon number 5 hydroxyl bonds to it, two different forms can result.
These two forms are identical except for the configuration around C1. These two forms are called anomers.
C1 is called the anomeric carbon. If the hydroxyl group on C1 and the -CH2OH group on C5 are on opposite sides of the six-membered ring, C1 is known to be the a anomer.
If they are on the same side, C1 is known to be the β anomer.
(e)
Interpretation:
The monosaccharide formed when sophorose is hydrolyzed needs to be determined.
Concept Introduction:
Disaccharides are carbohydrates composed of two monosaccharides.
Disaccharides are acetals, compounds that contain two alkoxy groups (OR groups) bonded to the same carbon.
A disaccharide results when a hemiacetal of one monosaccharide reacts with a hydroxyl group of a second monosaccharide to form an acetal. The new C-O bond that joins the two rings together is called a glycosidic linkage.
The two monosaccharide rings may be five-membered or six-membered. All disaccharides contain at least one acetal that joins the rings together. Each ring is numbered beginning at the anomeric carbon, the carbon in each ring bonded to two oxygen atoms.
The hydrolysis of a disaccharide cleaves the C-O glycosidic linkage and forms two monosaccharides.
Want to see the full answer?
Check out a sample textbook solutionChapter 20 Solutions
GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES
- Justify the polymerization of vanadates VO43-, as a function of concentration and pH.arrow_forwardWhat is the preparation of 500 mL of 100mM MOPS buffer (pH=7.5) starting with 1 M MOPS and 1 M NaOH? How would I calculate the math?arrow_forwardIndicate the correct option.a) Isopolianions are formed around metallic atoms in a low oxidation state.b) Non-metals such as N, S, C, Cl, ... give rise to polyacids (oxygenated).c) Both are incorrect.arrow_forward
- 14. Which one of the compounds below is the major organic product obtained from the following series of reactions? Br OH OH CH3O™ Na+ H*, H₂O SN2 HO OH A B C D 0 Earrow_forwardWavelength (nm) I'm not sure what equation I can come up with other than the one generated with my graph. Can you please show me the calculations that were used to find this equation? Give an equation that relates energy to wavelength. Explain how you arrived at your equation. Wavelength Energy (kJ/mol) (nm) 350 341.8 420 284.8 470 254.5 530 225.7 580 206.3 620 192.9 700 170.9 750 159.5 Energy vs. Wavelength (Graph 1) 400 350 y=-0.4367x+470.82 300 250 200 150 100 50 O 0 100 200 300 400 500 600 700 800 Energy (kJ/mol)arrow_forward5. Draw molecular orbital diagrams for superoxide (O2¯), and peroxide (O2²-). A good starting point would be MO diagram for O2 given in your textbook. Then: a) calculate bond orders in superoxide and in peroxide; indicate which species would have a stronger oxygen-oxygen bond; b) indicate which species would be a radical. (4 points)arrow_forward
- 16. Which one of the compunds below is the final product of the reaction sequence shown here? عملاء .OH Br. (CH3)2CH-C=C H+,H,O 2 mol H2, Pt A OH B OH D OH E OH C OHarrow_forwardIndicate whether any of the two options is correct.a) The most common coordination structure for isopolianions is the prismb) Heteropolianions incorporate alkaline cations into their structuresarrow_forwardPlease correct answer and don't use hand ratingarrow_forward
- Wavelength (nm) I'm not sure what equation I can come up with other than the one generated with my graph. Can you please show me the calculations that were used to find this equation? Give an equation that relates energy to wavelength. Explain how you arrived at your equation. Wavelength Energy (kJ/mol) (nm) 350 341.8 420 284.8 470 254.5 530 225.7 580 206.3 620 192.9 700 170.9 750 159.5 Energy vs. Wavelength (Graph 1) 400 350 y=-0.4367x+470.82 300 250 200 150 100 50 O 0 100 200 300 400 500 600 700 800 Energy (kJ/mol)arrow_forward6. For the following molecules: draw Lewis dot-structures; use VSEPR method to determine geometries of the following molecules/ions. Are the central atoms in these molecules/ions considered of normal valency, or are they hypervalent? (please read paragraph 2.6) a) BrF3 (6 points) b) BrF4 c) IF₂ 4arrow_forwardNonearrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co