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- Three compounds (A, B and C) are mixed together ( they are present in the same container). Molar absorptivity coefficients of these compounds at 575nm -1 -1 are: 2500, 3750 and 5250Lcm mol, respectively. Concentrations are: 2 × 10M for A, 5× 105 M for B and -6 1.5×10 M for C. What is the absorbance measured at 575mm, in 1.0cm cuvette of the solution containing all three compounds? Show your calculations.A 2.0 gram of a certain substance with a molecular weight of 100 g/mol is dissolved in a 500 ml solution. The length of the cuvette is 2.0 cm and absorbance of 0.301. What is the extinction coefficient in cm-1 M-1?7) The correct structure that corresponds to the spectroscopic data given below is [IR 2720, 1710 1 point cm*1. 1H NMR 9.80(s, 1H), 7.50(dd, J = 8,0Hz, 2Hz, 1H), 7.40(d, J = 2.0Hz, 1H), 6.90(d, J = 8.0Hz, 1H), 3.90(s, 3H), 3.80(s, 3H)] COOH OMe Me CHO OMe OMe CHO OMe OMe COOH OMe Me
- Calculate and report the energy, in units of joules, associated with each absorbance maximum.the absorbance of an equilibrium mixture of Fescn2+ was measured at 447nm and found to be 0.319. What is the equilibrium concentration of FeSCN2+?Please help me with this, I am trying to prepare for my final exam next week and I am just completely lost
- 3) A compound, X, with a molecular weight of 292.16 g/mol was dissolved in a 5.00 mL volumetric flask and diluted to the mark. A 1.00 mL aliquot of this was withdrawn, placed into a 10.00 mL volumetric flask and diluted to the mark. The absorbance at 340 nm was 0.427 in a 1.000 cm cuvette. The molar absorptivity of X at 340 nm is 6130 M-¹ cm-¹ a) Using Beer's Law, what is the [X] (concentration in molarity) for the diluted solution in the cuvet ? mmmmm b) Use the dilution equation (McVc = MdVa) to calculate [X] in the original 5.00 mL flask. c) How many milligrams of X was used in the original solution ? (Find total moles X using original concentration and original volume - and then use the molar mass to go from moles to grams and then milligrams)Identify, synthesized and show the mechanism show in the spectroscopy4. The total absorbance of a solution is the sum of the absorbances of all different materials present. AT = Aa + Ap + Ac .. etc. At 427 nm, the molar absorbtivity of Yellow #5 is 2.73×10°M-1-cm1. At 427 nm the molar absorptivity of Red 40 is 7.49x103 M-1.cm-1. Calculate the total absorbance of a solution in which the concentration of Yellow #5 = 2.00x10-5 M and the concentration of Red 40 = 4.80x10-5 M, when measured at 427 nm in a 1.00 cm cell.
- A substance is known to have a molar extinction coefficient of 18,300mlxcm-1xmg-1 at its wavelength of maximum absorption. The absorption of a solution containing this substance in a 1-cm sample cell was found to be 0.327 at this same wavelength. Determine the concentration of the solution.If a radiation intensity l0 = 2.5x1010 fotones s-1 cm2 causes a dissolución and an absorbance of 0.95 will be recorded. How much incident radiation is absorbed by the music screen?2. The molar absorptivity of compound A & B were measured with pure solutions as follows: wavelength (nm) Ea (M'cm-') 2139 EB (M-'cm-') 8469 312 417 10892 4325 (a) Calculate the frequency at wavelength of 312 nm and 417 nm. What wavelength has the greatest frequency? What wavelength has the greatest energy (show your calculation)? (b) A mixture of compound A and B in a 1.00 cm cell had an absorbance of 0.543 at 312 nm and 0.762 at 417 nm. Find the concentrations of A and B in the sample. 3. Given the molar absorptivity of a pH indicator at 525 nm is 16884 M-'cm for In and 1125 M-'cm- for HIn, calculate the pKa of the indicator if the absorbance of a 8.40 X 105 M solution of the indicator at pH 5.48 is 0.412 using a 1.00 cm cell.
