7) The correct structure that corresponds to thespectroscopic data given below is [IR 2720, 17101 pointcm*1. 1H NMR 9.80(s, 1H), 7.50(dd, J = 8,0Hz, 2Hz, 1H),7.40(d, J = 2.0Hz, 1H), 6.90(d, J = 8.0Hz, 1H), 3.90(s,3H), 3.80(s, 3H)]COOHOMeMeCHOOMeOMeCHOOMeOMeCOOHOMeMe

compound contains aldehydic group not carboxylic group as HNMR shows peak at 9.8 ppm which is region…

Answered: 7) The correct structure that…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL3: Carbon (13c) Nmr Spectroscopy

Section: Chapter Questions

Problem 9CTQ

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What would be the ratio N(-1/2)/N(+1/2) of the number of protons in spin state (-1/2) over (+1/2) state at a very low temperature of 3K (liquid He boiling pt) and in a 800 MHz NMR spectrometer?
NMR data Summary NMR solvent: DMSO-d6 'H NMR: Splitting (Multiplicity) Integration Chemical Shift 9.67 singlet 1H singlet doublet 9.17 7.37 6.72 2.00 1H 2H doublet singlet 2H 3H 1"C NMR: Chemical Shift 167.8 153.3 131.1 121.1 115.1 23.8 15N NMR: Chemical Shift 132.3 Instructions: Step 0: Look at the structure of Tylenol. Determine integration, and splitting you are expecting in the 'H NMR. Step 1: Look at the integration and splitting of the signals in the H NMR spectrum - assign the chemical shift of the protons of the methyl group; make a note which signals in the 'H NMR are due aromatic protons, NH and/or OH. Step 2: Look at the 'HSN HSQC spectrum - Use this spectrum to assign the chemical shifts of the NH proton and the OH proton. Step 3: Look at the 'H1SN HMBC spectrum - Use this spectrum to assign the chemical shifts of the aromatic protons in the 'H NMR. Step 4: Look at the 13C NMR spectrum - Make a note which carbon atoms are aromatic and/or alkyl. Assign the chemical shift of…
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7) The correct structure that corresponds to the spectroscopic data given below is [IR 2720, 1710 1 point cm*1. 1H NMR 9.80(s, 1H), 7.50(dd, J = 8,0Hz, 2Hz, 1H), 7.40(d, J = 2.0Hz, 1H), 6.90(d, J = 8.0Hz, 1H), 3.90(s, 3H), 3.80(s, 3H)] COOH OMe Me CHO OMe OMe CHO OMe OMe COOH OMe Me