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- 7) The homogeneity of the chloride level in a water sample from a lake was tested by an analyst. Below are the concentration in parts per million (ppm) of Cl: 27.32, 27.22, 27.21, 27.24, 27.20 i. Determine the mean and median. ii. Calculate the confidence limit at 90%. iii. Identify a possible outlier and use the Q-test to determine whether it can be retained or rejected at 90% confidence level4. A fat sample with combination of acids contain standard hydrochloric acid for blank and sample with 8mL and 5mL respectively. The normality of the standard hydrochloric acid is 0.93N and the weight of the sample is 3 grams. Calculate the saponification value.If an instrument gives a response of 1240 for a standard containing 8 ppm of a substance, how much if this substance is in a sample that gives a response of 1705? Are any assumptions needed?
- What is the minimum distribution coefficient that permits removal of 99% of a solute from 50.0 mL of water with a two 50.0-mL extractions with toluene? Distribution coefficient = = b five 45.0-mL extractions with toluene? Distribution coefficient =When pure furfural (solvent) is added to a mixture containing 0.2 mass fraction diphenylhexane and 0.8 mass fraction docosane, two separate layers can be obtained. If the composition of the two layers are as shown in the table, how much solvent was added to 500 kg of solution of docosane and diphenylhexane?Study the tabulated data during an gravimetric analysis of BaSO4 experiment Trial T1 T2 T3 Mass of sample (g) 1.0040 1.0100 1.0050 Constant weight of empty crucible (g) 10.2453 10.2454 10.2454 Constant weight after ignition (g) 10.3253 10.3252 10.3253 1. Calculate the mean mass of precipitate as BaSO4 a. 0.0799 g b. 0.0800 c. 0.08 g 2. Calculate the mean weight of sulphate (MM BaSO4 = 233.39 g/mol, So42- = 176 g/mol)? a. 0.0603 g b. 0.06 g c. 0.06025 g 3. Calculate the mean % SO42- in the sample a. 6.00% b. 5.991% c. 5.9908%
- Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?An HPLC method was developed for the separation and determination of ibuprofen in blood samples. A 3.00 mL blood sample dissolved in 70.00 mL solvent was prepared and 10.0 mL was injected into the HPLC. Standard ibuprofen solutions were also run.Calculate the ibuprofen present in the 3.00 mL blood sample The following data were obtained. Table po itoo: Ibuprofen concentration, mg/ml0.50 1.0 2.0 3.0 Blood sample Peak area (Right column)5.29.617.419.911.4Analysis of a standard solution at a concentration of 5 ppm Fe (III) is done with a new analysis method. The experiment is repeated 3 times, and the average iron ion concentration is determined as 4.7 ppm. The standard deviation, s = 0.1, is calculated according to the results of the three experiments. Does the new analysis method contain systematic errors at a 95% confidence level? (Choose the t value from the Table) t values Degrees of freedom 95% CL 1 12.7 4.3 3.18 4 2.78 O a. A systematic error exists O b. Only random error exists
- 18. You need to dilute 10 M sulfuric acid to 0.5 M sulfuric acid for your experiment. You plan to use 100 mL of your diluted solution. How much of the concentrated solution do you need? Hint use M₁V₁=M₂V₂ 0.5 mL 5 mL C. 50 mL d. 500 mL a. b. (10M)V₁ = (0.5)(100ml) sob (10) = 500 1.05 10The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with D water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. Which of the following technique can be used to determine the amount of mercury in the undiluted sample of river water? O A. IR spectroscopy O B. Cold vapor atomic absorption OC. Hydride generation atomic absorption OD. Electrothermal atomic absorption