3) A compound, X, with a molecular weight of 292.16 g/mol was dissolved in a 5.00 mL volumetric flask and diluted to the mark. A 1.00 mL aliquot of this was withdrawn, placed into a 10.00 mL volumetric flask and diluted to the mark. The absorbance at 340 nm was 0.427 in a 1.000 cm cuvette. The molar absorptivity of X at 340 nm is 6130 M-¹ cm-¹ a) Using Beer's Law, what is the [X] (concentration in molarity) for the diluted solution in the cuvet ? b) Use the dilution equation (McVc = MaVa) to calculate [X] in the original 5.00 ml flask. c) How many milligrams of X was used in the original solution ? (Find total moles X using original concentration and original volume - and then use the molar mass to go from moles to grams and then milligrams)
3) A compound, X, with a molecular weight of 292.16 g/mol was dissolved in a 5.00 mL volumetric flask and diluted to the mark. A 1.00 mL aliquot of this was withdrawn, placed into a 10.00 mL volumetric flask and diluted to the mark. The absorbance at 340 nm was 0.427 in a 1.000 cm cuvette. The molar absorptivity of X at 340 nm is 6130 M-¹ cm-¹ a) Using Beer's Law, what is the [X] (concentration in molarity) for the diluted solution in the cuvet ? b) Use the dilution equation (McVc = MaVa) to calculate [X] in the original 5.00 ml flask. c) How many milligrams of X was used in the original solution ? (Find total moles X using original concentration and original volume - and then use the molar mass to go from moles to grams and then milligrams)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![3) A compound, X, with a molecular weight of
292.16 g/mol was dissolved in a 5.00 mL volumetric
flask and diluted to the mark. A 1.00 mL aliquot of
this was withdrawn, placed into a 10.00 mL
volumetric flask and diluted to the mark. The
absorbance at 340 nm was 0.427 in a 1.000 cm
cuvette. The molar absorptivity of X at 340 nm is
6130 M-¹ cm-¹
a) Using Beer's Law, what is the [X]
(concentration in molarity) for the diluted solution in
the cuvet ?
mmmmm
b) Use the dilution equation (McVc = MdVa) to
calculate [X] in the original 5.00 mL flask.
c) How many milligrams of X was used in the
original solution ? (Find total moles X using
original concentration and original volume - and
then use the molar mass to go from moles to grams
and then milligrams)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbaa64798-ff50-47d6-b342-20b56281101d%2Fc2f324ed-56a7-4ee5-bf23-08584b0ef943%2F8l61qci_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3) A compound, X, with a molecular weight of
292.16 g/mol was dissolved in a 5.00 mL volumetric
flask and diluted to the mark. A 1.00 mL aliquot of
this was withdrawn, placed into a 10.00 mL
volumetric flask and diluted to the mark. The
absorbance at 340 nm was 0.427 in a 1.000 cm
cuvette. The molar absorptivity of X at 340 nm is
6130 M-¹ cm-¹
a) Using Beer's Law, what is the [X]
(concentration in molarity) for the diluted solution in
the cuvet ?
mmmmm
b) Use the dilution equation (McVc = MdVa) to
calculate [X] in the original 5.00 mL flask.
c) How many milligrams of X was used in the
original solution ? (Find total moles X using
original concentration and original volume - and
then use the molar mass to go from moles to grams
and then milligrams)
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