An unknown amount of a compound with a molecular mass of 270.57 g/mol is dissolved in a 10 mL volumetric flask. A 1.00 mL aliquot of this solution is transferred to a 25 mL volumetric flask, and enough water is added to dilute to the mark. The absorbance of this diluted solution at 355 nm is 0.495 in a 1.000 cm cuvette. The molar absorptivity for this compound at 355 nm is €355 = 6149 M-¹cm-¹. What is the concentration of the compound in the cuvette? concentration: What is the concentration of the compound in the 10 ml flask? concentration: How many milligrams of compound were used to make the 10 mL solution? mass: M M mg

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**Preparation and Analysis of a Compound Solution**

An unknown amount of a compound with a molecular mass of 270.57 g/mol is dissolved in a 10 mL volumetric flask. A 1.00 mL aliquot of this solution is transferred to a 25 mL volumetric flask, and enough water is added to dilute to the mark. The absorbance of this diluted solution at 355 nm is 0.495 in a 1.000 cm cuvette. The molar absorptivity for this compound at 355 nm is \( \varepsilon_{355} = 6149 \, \text{M}^{-1}\text{cm}^{-1} \).

### Questions

1. **What is the concentration of the compound in the cuvette?**
   - Concentration: \_\_\_\_\_\_\_\_ M

2. **What is the concentration of the compound in the 10 mL flask?**
   - Concentration: \_\_\_\_\_\_\_\_ M

3. **How many milligrams of compound were used to make the 10 mL solution?**
   - Mass: \_\_\_\_\_\_\_\_ mg 

**Instructions for Solving:**

To solve these questions, apply the Beer-Lambert Law:

\[ A = \varepsilon \cdot c \cdot l \]

Where:
- \( A \) is the absorbance (0.495),
- \( \varepsilon \) is the molar absorptivity (\(6149 \, \text{M}^{-1}\text{cm}^{-1}\)),
- \( c \) is the concentration in the cuvette in M,
- \( l \) is the path length of the cuvette (1.000 cm).

Calculate the concentration in the cuvette first, then use dilution principles to find the original concentration and mass in the 10 mL flask.
Transcribed Image Text:**Preparation and Analysis of a Compound Solution** An unknown amount of a compound with a molecular mass of 270.57 g/mol is dissolved in a 10 mL volumetric flask. A 1.00 mL aliquot of this solution is transferred to a 25 mL volumetric flask, and enough water is added to dilute to the mark. The absorbance of this diluted solution at 355 nm is 0.495 in a 1.000 cm cuvette. The molar absorptivity for this compound at 355 nm is \( \varepsilon_{355} = 6149 \, \text{M}^{-1}\text{cm}^{-1} \). ### Questions 1. **What is the concentration of the compound in the cuvette?** - Concentration: \_\_\_\_\_\_\_\_ M 2. **What is the concentration of the compound in the 10 mL flask?** - Concentration: \_\_\_\_\_\_\_\_ M 3. **How many milligrams of compound were used to make the 10 mL solution?** - Mass: \_\_\_\_\_\_\_\_ mg **Instructions for Solving:** To solve these questions, apply the Beer-Lambert Law: \[ A = \varepsilon \cdot c \cdot l \] Where: - \( A \) is the absorbance (0.495), - \( \varepsilon \) is the molar absorptivity (\(6149 \, \text{M}^{-1}\text{cm}^{-1}\)), - \( c \) is the concentration in the cuvette in M, - \( l \) is the path length of the cuvette (1.000 cm). Calculate the concentration in the cuvette first, then use dilution principles to find the original concentration and mass in the 10 mL flask.
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