10 cm 3 air saturated Fricke dosimetry solution in a 1 cm diameter tube is irradiated for 10 min in a 6~ source of gamma rays. The optical density measured at 304 txm in a 1 cm light path at 30~ was 0.260 after the completion of irradiation and 0.003 before irradiation. (a) What is the total dose in gray absorbed by the solution? (b) If 10 cm 3 of methanol is irradiated in the same tube for the same 10min, what is the absorbed dose in gray. The Z/A for methanol is 0.562 and that for the Fricke dosimeter is 0.553. Explain any assumption you make to solve the problem.
10 cm 3 air saturated Fricke dosimetry solution in a 1 cm diameter tube is irradiated for 10 min in a 6~ source of gamma rays. The optical density measured at 304 txm in a 1 cm light path at 30~ was 0.260 after the completion of irradiation and 0.003 before irradiation. (a) What is the total dose in gray absorbed by the solution? (b) If 10 cm 3 of methanol is irradiated in the same tube for the same 10min, what is the absorbed dose in gray. The Z/A for methanol is 0.562 and that for the Fricke dosimeter is 0.553. Explain any assumption you make to solve the problem.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 10 cm 3 air saturated Fricke dosimetry solution in a 1 cm diameter tube is irradiated for 10 min in a 6~ source of gamma rays. The optical density measured at 304 txm in a 1 cm light path at 30~ was 0.260 after the completion of irradiation and 0.003 before irradiation.
(a) What is the total dose in gray absorbed by the solution?
(b) If 10 cm 3 of methanol is irradiated in the same tube for the same 10min, what is the absorbed dose in gray. The Z/A for methanol is 0.562 and that for the Fricke dosimeter is 0.553. Explain any assumption you make to solve the problem.
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