GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES
GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES
4th Edition
ISBN: 9781265982959
Author: SMITH
Publisher: MCG
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Chapter 20, Problem 29P
Interpretation Introduction

(1)

Interpretation:

The chiral center needs to be labeled in each compound.

Concept introduction:

Chiral carbon is an asymmetric carbon which contains four different types of groups or atoms. Monosaccharides have one or more chiral centers except dihydroxyacetone.

Interpretation Introduction

(2)

Interpretation:

Need to classify the given molecules as D or L monosaccharides.

Concept introduction:

Sugar molecules can name as D or L sugars according to their most oxidized carbon at the top of the Fisher projection.

Interpretation Introduction

(3)

Interpretation:

Need to draw the enantiomers.

Concept introduction:

Carbon group with four different group attached are chiral. Those compounds and their mirror image are non −superimposable and these are called as enantiomers or optical isomers.

Interpretation Introduction

(4)

Interpretation:

Need to draw Fisher projection.

Concept introduction:

Fisher projection is a two dimensional representation of a three dimensional molecule.

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Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table  and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.

Chapter 20 Solutions

GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES

Ch. 20.3 - Prob. 20.3PPCh. 20.3 - Prob. 20.4PPCh. 20.4 - Prob. 20.5PPCh. 20.4 - Prob. 20.6PPCh. 20.4 - Prob. 20.9PCh. 20.4 - Prob. 20.10PCh. 20.5 - Prob. 20.7PPCh. 20.5 - Prob. 20.8PPCh. 20.5 - Lactose contains both an acetal and a hemiacetal....Ch. 20.5 - Prob. 20.12PCh. 20.5 - Prob. 20.13PCh. 20.5 - Prob. 20.14PCh. 20.5 - Prob. 20.15PCh. 20.6 - Prob. 20.16PCh. 20.6 - Prob. 20.17PCh. 20.7 - Prob. 20.18PCh. 20.7 - Prob. 20.19PCh. 20.8 - Prob. 20.20PCh. 20 - Prob. 21PCh. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Prob. 25PCh. 20 - Prob. 26PCh. 20 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Prob. 32PCh. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - What product is formed when each compound is...Ch. 20 - What product is formed when each compound is...Ch. 20 - Prob. 49PCh. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54PCh. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - Prob. 62PCh. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - Prob. 67PCh. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - Prob. 72PCh. 20 - Prob. 73PCh. 20 - Prob. 74PCh. 20 - Prob. 75PCh. 20 - Prob. 76PCh. 20 - Prob. 77PCh. 20 - Prob. 78PCh. 20 - Prob. 79CPCh. 20 - Prob. 80CP
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