A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn. Concept introduction: 1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

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Answer 1

Question

Chapter 20, Problem 63P

Interpretation Introduction

Interpretation:

A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.

Concept introduction:

1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

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Answer 2

Question

Chapter 20, Problem 63P

Interpretation Introduction

Interpretation:

A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.

Concept introduction:

1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

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Answer 3

Question

Chapter 20, Problem 63P

Interpretation Introduction

Interpretation:

A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.

Concept introduction:

1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

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Answer 4

Question

Chapter 20, Problem 63P

Interpretation Introduction

Interpretation:

A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.

Concept introduction:

1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

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Answer 5

Chapter 20, Problem 63P

Interpretation Introduction

Interpretation:

A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.

Concept introduction:

1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

Answer 6

Chapter 20, Problem 63P

Interpretation Introduction

Interpretation:

A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.

Concept introduction:

1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

Answer 7

Chapter 20, Problem 63P

Interpretation Introduction

Interpretation:

A segment of the polysaccharide formed by 3 galactose units joined together in 1-4 − α − linkages needs to be drawn.

Concept introduction:

1-4 − α − linkages are formed due to condensation reaction of a hydroxyl group on fourth carbon atom of one sugar with the anomeric first carbon of another sugar. β sign is given due to the position of the bonding hydroxyl group of anomeric carbon atom, which is below the ring.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 20.1 - Label the hemiacetal carbonthe carbon bonded to...Ch. 20.2 - Prob. 20.1PP Ch. 20.2 - Prob. 20.2P Ch. 20.2 - Prob. 20.3P Ch. 20.2 - Prob. 20.4P Ch. 20.2 - Prob. 20.5P Ch. 20.2 - Prob. 20.2PP Ch. 20.2 - Prob. 20.6P Ch. 20.2 - Prob. 20.7P Ch. 20.3 - Prob. 20.8P

Solution Summary: The author explains the structure of the polysaccharide formed by 3 galactose units joined together.

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Chapter 20 Solutions