Concept explainers
a.
To formulate: The concise genetic hypothesis, which explains the results of the blotched leaves and the symbols which show the classes of genotypes.
Introduction: The plant which has grown on Vancouver and British Columbia Mainland exhibit the dimorphism in the leaves notch in most of the leaves. Blotches are the irregular patterns of spots present on the leaves. The plant with no flowering was estimated by the scientists, to distinguish among recessiveness and dominance characters in progenies of the leaves at random.
b.
To test: The determined and specific hypothesis about the approval of the traits.
Introduction:
The plant, which was not able to be flowered under the natural and environmental soil conditions, was taken for the examination in the laboratory to define the character, which plant was exhibiting in dominance or which was exhibiting the recessive character. The crossing was performed in the laboratory so that the primary and dominant character of the parent plants can be determined.
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Introduction To Genetic Analysis
- A snapdragon with pink petals, black anthers, and longstems was allowed to self-fertilize. From the resultingseeds, 650 adult plants were obtained. The phenotypesof these offspring are listed here.78 red long tan26 red short tan44 red long black15 red short black39 pink long tan13 pink short tan204 pink long black68 pink short black5 white long tan2 white short tan117 white long black39 white short blacka. Using P for one allele and p for the other, indicatehow flower color is inherited.b. What numbers of red : pink : white would havebeen expected among these 650 plants?c. How are anther color and stem length inherited?d. What was the genotype of the original plant?e. Do any of the three genes show independentassortment?f. For any genes that are linked, indicate the arrangements of the alleles on the homologous chromosomes in the original snapdragon, and estimate thedistance between the genesarrow_forwardIn the following diagram, designate each daughter cell as diploid (2n) or haploid (n).arrow_forwardA man suffered from rare a skin condition that included thickening of the skin and the formation of loose spines that were periodically sloughed off. He was called by the locals as “porcupine man”. He married and had six sons, all of whom had the same condition. He also had three daughters, all of whom were unaffected. What might you theorize about the location of the abnormal gene? In maize, a dominant allele A is necessary for seed color, as opposed to colorless (a). Another gene has a recessive allele wx that results in waxy starch, as opposed to normal starch (Wx). The two genes segregate independently. An Aa WxWx plant is test crossed. What are the phenotypes and relative frequencies of offspring? (show the workflow to reach your answers) all sub-questions carries equal grades): Consider three gene pairs Aa, Bb, and Cc, each of which affects a different character. In each case, the uppercase letter signifies the dominant allele and the lowercase letter the recessive allele.…arrow_forward
- A variety of opium poppy (Papaver somniferum L.) with lacerate leaves was crossed with a variety that has normal leaves. All the F1 had lacerate leaves. Two F1 plants were interbred to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. Give genotypes for all the plants in the P, F1, and F2 generations. Explain how lacerate leaves are determined in the opium poppy.arrow_forwardLet us suppose that two plants are crossed (mated). One plant (female) is homozygous dominant and produces chlorophyll, and the other (male) is homozygous recessive and does not produce chlorophyll. These two plants are considered the parental, or P generation. What would be the possible genotypes and phenotypes of these two individuals? Fill in the table below with the parental generation's descriptional information. Table 6.1 Female Male Description Parental Generation Homozygous dominant P Generation Genotype gg Phenotype Greenarrow_forwardChoose which of the following is true: a) Haploid cells have one allele per gene b) Haploid cells have two alleles per genearrow_forward
- Nicotiana glutinosa (2 n = 24) and N. tabacum (2 n = 48) are two closely related plants that can be intercrossed, but the F1 hybrid plants that result are usually sterile. In 1925, Roy Clausen and Thomas Goodspeed crossed N. glutinosa and N. tabacum and obtained one fertile F1 plant . They were able to self-pollinate the flowers of this plant to produce an F2 generation. Surprisingly, the F2 plants were fully fertile and produced viable seeds. When Clausen and Goodspeed examined the chromosomes of the F2 plants, they observed 36 pairs of chromosomes in metaphase I and 36 individual chromosomes in metaphase II. Explain the origin of the F2 plants obtained by Clausen and Goodspeed and the numbers of chromosomes observed.arrow_forwardYou ave established a mutant line of flies with a balancer chromosome. The balancer chromosome includes GFP and a mutation in gene X that causes flies to be sterile in the homozygous state. The recessive mutation that you are studying is in gene Y, and causes flies to develop two tail ends in the homozygous state. This mutation is lethal in the homozygous state. For each of the following phenotypes in the balanced mutant line, what alleles are present and in how many copies? a.) Glows green, fertile (Select] b.) Glows green, sterile [Select) c.) does not glow green, two tails (Select] If you crossed a fly from your balanced line with the following flies, what proportion of the offspring would glow green and be fertile? d.) wild-type [Select ) e.) fly with balancer chromosome from parental generation [ Select ]arrow_forwardA plant has a genotype AaBb. there is no linkage of the genes. the gametes it will produce are: A) AB and ab B) Aa and Bb C) AA, aa, BB and Bb D) AB, Ab, aB and abarrow_forward
- A plant believed to be heterozygous for a pair of alleles B/b (where B encodes yellow and b encodes bronze) was selfed, and, in the progeny, there were 280 yellow and 120 bronze plants. Do these results support the hypothesis that the plant is B/b?arrow_forwardThis information pertains to questions 8 and 9. You suspect that the gene for round vs oval seeds and the gene for green vs. orange leaf color may be linked genes for a certain diploid plant species. You use a true-breeding plant for both round seeds and orange leaves to pollinate a plant true- breeding for oval seeds and green leaves. All their offspring have round seeds and green leaves. When the F1 is test-crossed, the following offspring are produced: 40 round seeds, orange leaves 10 round seeds green leaves 42 oval seeds green leaves 8 oval seeds orange leaves 8. Which two phenotypes are dominant? a. Oval seeds, orange leaves b. Round seeds, orange leaves c. Oval seeds, green leaves d. Round seeds, green leaves e. Can't tellarrow_forwardWild-type mice have brown fur and short tails. Loss of function of a particular gene produces white fur, while loss of function of another gene produces long tails, and loss of function at a third locus produces agitated behavior. Each of these loss of function alleles is recessive. If a wild-type mouse is crossed with a triple mutant, and their F1 progeny is test-crossed, the following recombination frequencies are observed among their progeny. Produce a genetic map for these loci. Brown, short tailed, normal: 955 White, short tailed, normal: 16 Brown, short tailed, agitated: 0 White, short tailed, agitated: 36 Brown, long tailed, normal: White, long tailed, normal: Brown, long tailed, agitated: 46 0 14 White, long tailed, agitated: 933arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning