Introduction To Genetic Analysis
12th Edition
ISBN: 9781319114787
Author: Anthony J.F. Griffiths, John Doebley, Catherine Peichel, David A. Wassarman
Publisher: W. H. Freeman
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Chapter 2, Problem 2P
Summary Introduction
To determine: The result obtained by cross-pollinating two different F1 plants.
Introduction: GregorMendel is known as the father of genetic because he proposed three laws of inheritance, and based on these laws,he developed pure lines and counted the results and kept the statistical notes. Mendel took seven characteristics of the pea plant and performed various type of crosses, using pea as a model
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You successfully isolate an hsf2/hsf2; hsf3/hsf3 double mutant stock. You cross this plant to an hsf1/hsf1 plant and then self-pollinate the F1. You want to recover at least 10 triple mutant homozygous to evaluate the phenotype. How many plants do you need to genotype to expect to recover 10 triple mutant plants?
A) Describe the data you collect from the Purple 1 x Purple 2 cross. Predict the genotype of each of the parent plants. Explain your predictions using data from the experiment.
B) Consider the offspring, the next generation (F1), from the Purple 1 x Purple 2 cross. What is the probability of a green stem plant? How do you know this?
C) What is the probability in the F2 generation of a green stem offspring? Use a Punnett square(s) and quantitative data to explain your thinking. Upload your Punnett square(s).
A) Describe the data you collect from the Purple 1 x Purple 2 cross. Predict the genotype of each of the parent plants. Explain your predictions using data from the experiment. (Again, you may need to use data from other crosses!)
B) Consider the offspring, the next generation (F1), from the Purple 1 x Purple 2 cross. What is the probability of a green stem plant? How do you know this?
C) What is the probability in the F2 generation of a green stem offspring? Use a Punnett square(s) and quantitative data to explain your thinking. Upload your Punnett square(s).
Chapter 2 Solutions
Introduction To Genetic Analysis
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 56.1PCh. 2 - Prob. 56.2PCh. 2 - Prob. 56.3PCh. 2 - Prob. 56.4PCh. 2 - Prob. 56.5PCh. 2 - Prob. 56.6PCh. 2 - Prob. 56.7PCh. 2 - Prob. 56.8PCh. 2 - Prob. 56.9PCh. 2 - Prob. 56.10PCh. 2 - Prob. 56.11PCh. 2 - Prob. 56.12PCh. 2 - Prob. 56.13PCh. 2 - Prob. 56.14PCh. 2 - Prob. 56.15PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 1GSCh. 2 - Prob. 2GSCh. 2 - Prob. 3GS
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- You self an F1 plant that is heterozygous for two dominant resistance genes, R1 and R2 and inoculate the F2 progeny with a pathogen race that is avirulent on both R1 and R2 (it carries both avirulence genes Avr1 and Avr2).You get 40 susceptible progeny out of 200 total progeny. (a) What is the linkage phase for these two genes? (b) What is the recombination distance?arrow_forwardGgTt pea plants can produce _____ type(s) of gamete(s), but a ggtt plant can produce _____ type(s) of gamete(s). explainarrow_forwardIn the left-hand part of Figure 2-4, the red arrows showselfing as pollination within single flowers of one F1plant. Would the same F2 results be produced by crosspollinating two different F1 plants?arrow_forward
- In tomatoes, the red fruit color is completely dominant to yellow. Suppose a tomato plant homozygous for red is crossed with one homozygous for yellow and the progeny are allowed to self pollinate. What phenotypes do you predict in the F2 generation? a) 3 red: 1 yellow b) 9 red : 3 orange : 1 yellow c) 1 red : 2 orange : 1 yellow d) 1 red : 1 yellowarrow_forwardif a plant is an auto-tetraploid with the genotype A1A1A2A2, what is the frequenct of offspring with the genotype A1A1A1A1 following self-fertilization of the plantarrow_forwardA horticulturist runs a test cross with an offspring (F1 generation) purple plant from Question 8. The phenotypic frequencies of the resulting offspring are 50% white and 50% purple. What is the true genotype of this offspring (F1 generation) purple plant?arrow_forward
- Flower color in petunias is determined by the biochemical pathway shown below: A_ B_ C_ Yellow Orange > Green Blue aa bb Plants of genotype AAbbcc were mated to plants of genotype AaBbCc. Determine the phenotypic ratio expected from this cross and fill in the spaces in the ratio below with whole numbers in lowest form. lf none are expected in a class, then type the number 0 in the space. Yellow: Orange : Green: Bluearrow_forwardYou make a test cross between an F1 plant that is heterozygous for two dominant resistance genes (R1 and R2) and a line that is homozygous recessive at both loci, and inoculate the progeny with a pathogen race that is avirulent on both R1 and R2 (i.e., it carries avirulence genes Avr1 and Avr2).You get 50 susceptible progeny out of 200 test cross progeny. (a) What is the linkage phase for these two genes? (b) What is the recombination distance?arrow_forwardRound (R) seed shape is dominant to wrinkled (r) seed shape in pea plants. If an RR plant is crossed with an rr plant, what is the frequency of phenotypes in the F2 generation? 1)1/4 RR, 1/2 Rr, 1/4 rr 2) All round seeds 3) 3 roundseeds, 1 wrinkled seed 4) All wrinkled seedsarrow_forward
- Maize is a highly cross-pollinated crop and heterotic phenomenon is evident from the currently available hybrids. If you are given a huge random germplasm pool of maize, what procedure you will adopt to develop competitive high yielding hybrids.arrow_forwardTall plant (D) is dominant to dwaf (d), and purple flower color (W) is dominant to white flower color (w). In order to determine the genotype of a tall plant with purple flowers, you decide to conduct a test cross. What should be the genotype of the plant you use to carry out the test cross?arrow_forwardLet P = purple flowers and p = white, and T = tall plants and t = dwarf. What are the genotypes of the gametes that are produced by a plant that is heterozygous for both traits? hint* This is a dihybrid self cross of an F1 heterozygous generation. O Tt, TT, tt, Pp, PP, and pp P, p, T, and t PT, Pt, pT, and pt PT and ptarrow_forward
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