Introduction To Genetic Analysis
12th Edition
ISBN: 9781319114787
Author: Anthony J.F. Griffiths, John Doebley, Catherine Peichel, David A. Wassarman
Publisher: W. H. Freeman
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Chapter 2, Problem 3P
Summary Introduction
To determine: The possibility of finding a pod with all yellow or green seeds.
Introduction: The monohybrid cross is a cross between the parents that differ in a single pair of the gene, whereas the dihybrid cross is the cross between two organisms, which are heterozygous for two different types of traits.
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A) Describe the data you collect from the Purple 1 x Purple 2 cross. Predict the genotype of each of the parent plants. Explain your predictions using data from the experiment. (Again, you may need to use data from other crosses!)
B) Consider the offspring, the next generation (F1), from the Purple 1 x Purple 2 cross. What is the probability of a green stem plant? How do you know this?
C) What is the probability in the F2 generation of a green stem offspring? Use a Punnett square(s) and quantitative data to explain your thinking. Upload your Punnett square(s).
In corn, the allele f ′ causes floury endosperm and the allele f ″ causes flinty endosperm. In the cross f ′/f ′ ×f ″/f ″, all the progeny endosperms are floury, but, in the reciprocal cross, all the progeny endosperms are flinty. What is a possible explanation? (Check the legend for Figure 2-7.)
In a trihybrid cross of a tall, purple-flowered pea plant with round seeds (TtPpRr) with a short, white-
flowered pea plant with round seeds (ttppRr), what is the probability:
A) that a short, white-flowered plant with wrinkled seeds will be produced?
B) that a tall, purple-flowered plant with round seeds will be produced?
C) that a tall, white-flowered plant with round seeds will be produced?
Chapter 2 Solutions
Introduction To Genetic Analysis
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 56.1PCh. 2 - Prob. 56.2PCh. 2 - Prob. 56.3PCh. 2 - Prob. 56.4PCh. 2 - Prob. 56.5PCh. 2 - Prob. 56.6PCh. 2 - Prob. 56.7PCh. 2 - Prob. 56.8PCh. 2 - Prob. 56.9PCh. 2 - Prob. 56.10PCh. 2 - Prob. 56.11PCh. 2 - Prob. 56.12PCh. 2 - Prob. 56.13PCh. 2 - Prob. 56.14PCh. 2 - Prob. 56.15PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 1GSCh. 2 - Prob. 2GSCh. 2 - Prob. 3GS
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- In a certain plant, the seed traits are as follows: Color: white (W) is dominant over yellow (w)Shape: disk (D) is dominant over sphere (d)Seed coat: thick (T) is dominant over thin (t) a) If the parent plant is a triple heterozygote, what is its phenotype? b) Analyzing the phenotypes of the offspring, the alleles of the gametes were determined as: 85 wDt 390 WDT 27 WDt 81 WdT5 wDT 374 wdt 30 wdT 8 Wdt construct a genetic map using the three-point cross.arrow_forward1) S-Tu-U 2) S-U-Tu 3) Tu-S-U 4) U-S-Tuarrow_forwardA male plant with genotype AaBBCcDdee was crossed with one heterozygous for all thegenes. (a) what is the probability of getting a pollen with ABcDe genes? (b) of producing anovum with three dominant and two recessive genes? (c) of getting a progeny with samephenotype as the female parent? (d) of progeny with exactly same genotype as the femaleparent? (e) If instead of the above male, the cross was with one heterozygous for all thegenes, what proportion of the offspring will have three dominant phenotypic traits. (f) willbe genotypically like the parents?arrow_forward
- regular (2) are tobed and serrated and potato teaves (4) are broad, smooth, and singte (Image 1). Re. Is dominlant to yellow fruit (). Image 1. Potato leaves (left) and regular leaves (right). A cross is carried out between two pure lines of tomato plants, one having regular leaves and red fruit and the other having potato leaves and yellow fruit. The F1 generation all have regular leaves and red fruit. The F1 individuals are then crossed with one another. Complete a Punnett square to determine the expected F2 progeny on the basis of Mendel's Law of Independent Assortment, which states that the alleles for one gene segregate independently of the alleles for other genes during gamete formation.arrow_forwardYou have already localized the genes to the same chromosome by deletion mapping, and now decide that the best way to accomplish the mapping is to conduct two simultaneous three-point testcross experiments. The genes you are investigating are as follows: N = round leaves, n = notched leaves; H = smooth stems, h = hairy stems; R = purple flowers, r = red flowers; B = grey seeds, b = black seeds; and Y = green pods, y = yellow pods. Earlier experiments you have done already established that gene B is in the middle of this gene cluster, so you design both three-point test crosses to include that gene. Cross #1 is designed as RrHhBb x rrhhbb while cross #2 is NnBbYy x nnbbyy. The results of both crosses are given in the table below. Based on the information given, determine the arrangement of these five genes including the position of each allele in the heterozygous fly and the distances between each pair of genes. (Hint: treat each experiment separately, knowing that gene B is in the…arrow_forwardIn Figure 5-32, what do the half-red, half-blue segments represent?arrow_forward
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