Chapter 2, Problem 2.27P

Interpretation Introduction

Interpretation:Mass number and number of protons, neutron, and electrons of each isotope $\text{C}\text{l}$ and $\text{C}\text{l}$ is to be determined.

Concept introduction:Mass number $\left(\text{A}\right)$ for a chemical element is defined as total number of neutrons and protons in an atomic nucleus. Mass number for each element is approximately equal to the atomic mass units. Mass number is different for each isotope of element.

Atomic number $\left(\text{Z}\right)$ for an element is defined as number protons present in nucleus of every element. For a neutral atom, atomic number is same as number of electrons present in outer orbital.

Formula to calculate neutron number in nucleus is as follows:

  $\text{Neutron number}\text{=}\text{Mass}\text{number}\left(\text{A}\right)-\text{Atomic}\text{number}\left(\text{Z}\right)$