Principles of General Chemistry
Principles of General Chemistry
3rd Edition
ISBN: 9780073402697
Author: SILBERBERG, Martin S.
Publisher: McGraw-Hill College
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Chapter 2, Problem 2.75P

(a)

Interpretation Introduction

Interpretation:Molar mass and number of H atoms C6H5COONH4 should be determined.

Concept introduction:Molecular mass of a chemical compound is defined as sum of masses of all atoms contained in a molecule.

The formula to calculate molecular mass of compound is as follows:

  Molecular mass of compound=[Σ(number of atoms of element)(atomic mass of element)]

(a)

Expert Solution
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Explanation of Solution

A molecular is a representation of a molecule by chemical symbol to indicate different types of atoms and how each atom connected. Here the number of hydrogen atoms in C6H5COONH4 is 9 atoms.

Formula to calculate molar mass of C6H5COONH4 is as follows:

  Molecular mass=[(7)(atomic mass of C)+(9)(atomic mass of H)+(2)(atomic mass of O)+(1)(atomic mass of N)]

Atomic mass of C is 12.01 amu .

Atomic mass of O is 16 amu .

Atomic mass of N is 14.01 amu .

Atomic mass of H is 1.008 amu .

Substitute the values in the above formula.

  Molecular mass=[( 7)( atomic mass of C)+( 9)( atomic mass of H)+( 2)( atomic mass of O)+( 1)( atomic mass of N)]Molecular mass=[( 7)( 12.01 amu)+( 9)( 1.008 amu)+( 2)( 16 amu)+( 1)( 14.01 amu)]=84.07 amu+9.072 amu+32 amu+14.01 amu=139.15 amu

(b)

Interpretation Introduction

Interpretation: Molar mass and number of N atoms N2H6SO4 should be determined.

Concept introduction:Molecular mass of a chemical compound is defined as sum of masses of all atoms contained in a molecule.

The formula to calculate molecular mass of compound is as follows:

  Molecular mass of compound=[Σ(number of atoms of element)(atomic mass of element)]

(b)

Expert Solution
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Explanation of Solution

A molecular is a representation of a molecule by chemical symbol to indicate different types of atoms and how each atom connected. Here the number of N atoms in N2H6SO4 is 2 atoms.

Formula to calculate molar mass of N2H6SO4 is as follows:

  Molecular mass=[(2)(atomic mass of N)+(6)(atomic mass of H)+(1)(atomic mass of S)+(4)(atomic mass of O)]

Atomic mass of S is 32.06 amu .

Atomic mass of O is 16 amu .

Atomic mass of N is 14.01 amu .

Atomic mass of H is 1.008 amu .

Substitute the values in the above equation.

  Molecular mass=[( 2)( atomic mass of N)+( 6)( atomic mass of H)+( 1)( atomic mass of S)+( 4)( atomic mass of O)]=[( 2)( 14.01 amu)+( 6)( 1.008 amu)+( 1)( 32.06 amu)+( 4)( 16 amu)]=28.02 amu+9.072 amu+32.06 amu+64 amu=130.13 amu

(c)

Interpretation Introduction

Interpretation: The number of O atoms and molar mass Pb4SO4(CO3)(OH)22 should be determined.

Concept introduction:Molecular mass of a chemical compound is defined as sum of masses of all atoms contained in a molecule.

The formula to calculate molecular mass of compound is as follows:

  Molecular mass of compound=[Σ(number of atoms of element)(atomic mass of element)]

(c)

Expert Solution
Check Mark

Explanation of Solution

A molecular is a representation of a molecule by chemical symbol to indicate different types of atoms and how each atom connected. The number of O atoms in Pb4SO4(CO3)(OH)22 is 12 atoms.

Formula to calculate molar mass of Pb4SO4(CO3)(OH)22 is as follow

  Molecular mass=[(4)(atomic mass of Pb)+(1)(atomic mass of S)+(2)(atomic mass of C)+(12)(atomic mass of O)+(2)(atomic mass of H)]

Atomic mass of Pb is 207.2 amu .

Atomic mass of S is 32.06 amu .

Atomic mass of O is 16 amu .

Atomic mass of N is 14.01 amu .

Atomic mass of H is 1.008 amu .

Substitute the value in the above equation.

  Molecular mass=[( 4)( atomic mass of Pb)+( 1)( atomic mass of S)+( 2)( atomic mass of C)+( 12)( atomic mass of O)+( 2)( atomic mass of H)]=[( 4)( 207.2 amu)+( 1)( 32.06 amu)+( 2)( 12.01 amu)+( 12)( 16 amu)+( 2)( 1.008 amu)]=828.8 amu+32.06 amu+24.02 amu+192 amu+2.016 amu=1078.9 amu

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Chapter 2 Solutions

Principles of General Chemistry

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