Interpretation: Quantity of 99Tc left after 1 day from a sample of 200 g must be determined.
Concept introduction: In a nuclear reaction, unstable nuclide disintegrates into stable nuclide with emission of various radiations spontaneously. It is called radioactivity of nucleus. Emission of rays like alpha, beta and gamma rays occur in the process which changes the identity of nucleus.
During a nuclear change, an element undergoes change in its
Answer to Problem 3STP
Quantity of 99Tc left after 1 day from a sample of 200 g is 12.5 g . Correct option is D.
Explanation of Solution
Given information: Elapsed time is 1 days that is 24 hr , mass of 99Tc sample is 200 g and half life is 6 hr .
The formula to calculate the number of half lives ( n) is as follows:
n=tT
Where,
n is number of half lives.
t is the elapsed time.
T is the half life of radioactive nucleus.
Substitute 24 hr for t , 6 hr for T in above equation.
n=tT=24 hr6 hr=4
Number of half lives equal to 4 .
The formula to calculate the remaining amount of radioactive element is as follows:
N=N0(12)n
Where,
n is number of half lives.
N0 is the initial amount of radioactive element.
N is the remaining amount of radioactive element.
Substitute 4 for n , 200 g for N0 in above equation.
N=N0(12)n=(200 g)(12)4=12.5 g
Quantity of 99Tc left after 1 day from a sample of 200 g is 12.5 g .
Since the quantity of 99Tc left after 1 day from a sample of 200 g is 12.5 g . Therefore option A,B and C are incorrect.
Chapter 19 Solutions
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