World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 19, Problem 2STP
Interpretation Introduction

Interpretation: Nuclear equation given has to be completed.

Concept introduction: Nuclear reactions are those where an unstable nuclide disintegrates in order to form a stable nuclide with emission of various radiations feasibly. It is called radioactivity of nucleus. The particles or rays emitted during the process are alpha, beta and gamma rays which cause a change in the identity of nucleus.

Beta particle is one that has unit negative charge and alpha particle is one that has 2 unit positive charges and is equivalent to helium atom 24He .

Expert Solution & Answer
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Answer to Problem 2STP

Complete equation is 2965Cu+612C301n+3574Br .Correct option is D.

Explanation of Solution

For reaction, 2965Cu+612C301n+?

Missing particle is 3574Br . It is so because 3 neutron particles are emitted on the reaction. In any nuclear equation, atomic number (Z) and mass remains (A) intact. Neutron has no Z. So the new element formed will have sum of 29 and 6. Due to loss of 3 neutron, new A comes out to 74.

Conclusion

After loss of 3 01n , A must 74 and Z must be 35, so option A,B and C are incorrect.

Complete equation is 2965Cu+612C301n+3574Br .Correct option is D.

Chapter 19 Solutions

World of Chemistry

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