Chapter 19, Problem 28A

Interpretation Introduction

Interpretation: Reason and balanced equation for the production of ${}_6^{14}C$ is to be given.

Concept introduction: ${}_6^{14}C$ is produced in the atmosphere as a result of a nuclear reaction. Balancing of nuclear reaction involves equating the number of nucleons and charges on both the sides of the equation where $m$ the number of nucleons is and $n$ is the charge on nucleus in ${}_n^{m}X$ .

Answer to Problem 28A

  ${}_6^{14}C$ is produced by a nuclear reaction between a Nitrogen-14 isotope and a neutron. Balanced equation for the process is as follows:

  ${}_7^{14}N+{}_0^{1}n$${}_6^{14}C+{}_1^{1}p$

Explanation of Solution

Nitrogen-14 isotope and cosmic rays are present in the atmosphere. A neutron from cosmic rays strikes the Nitrogen-14 isotope resulting in the formation of a Carbon-14 isotope and a proton. The equation is balanced as the number of nucleons is 15 on both the sides and charge is 7 on both the sides.

Conclusion

  ${}_6^{14}C$ is produced by a nuclear reaction between a Nitrogen-14 isotope and a neutron in which a proton is produced as a side product.