
Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Textbook Question
Chapter 19, Problem 33P
Predict the products from each of the following aldol reactions.
(a)
(b)
(c)
(d)
(e)
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For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 19 Solutions
Organic Chemistry
Ch. 19 - PRACTICE PROBLEM 19.1 (a) Write a mechanism. for...Ch. 19 - Practice Problem 19.2
Since the products obtained...Ch. 19 - Prob. 3PPCh. 19 - PRACTICE PROBLEM 19.4
Write mechanisms that...Ch. 19 - Prob. 5PPCh. 19 - Prob. 6PPCh. 19 - Practice Problem 19.7 The acid-catalyzed aldol...Ch. 19 - Prob. 8PPCh. 19 - Practice Problem 19.9
(a) Provide a mechanism for...Ch. 19 - Prob. 10PP
Ch. 19 - Practice Problem 19.11 Outlined below is a...Ch. 19 - Prob. 12PPCh. 19 - Prob. 13PPCh. 19 - Prob. 14PPCh. 19 - Practice Problem 19.15
Starting with ketones and...Ch. 19 - Practice Problem 19.16 Assuming that dehydration...Ch. 19 - Practice Problem 19.17 What starting compound...Ch. 19 - Practice Problem 19.18
What experimental...Ch. 19 - Prob. 19PPCh. 19 - Practice Problem 19.20
When acrolein (propenal)...Ch. 19 - Prob. 21PPCh. 19 - PRACTICE PROBLEM 19.22
Qutline reasonable...Ch. 19 - Prob. 23PCh. 19 - Show all steps in the following syntheses. You may...Ch. 19 - Prob. 25PCh. 19 - Prob. 26PCh. 19 - Prob. 27PCh. 19 - 19.28 Show how the diketone at the right could be...Ch. 19 - Prob. 29PCh. 19 - 19.30 Write a detailed mechanism for the following...Ch. 19 - Prob. 31PCh. 19 - Prob. 32PCh. 19 - 19.33 Predict the products from each of the...Ch. 19 - Prob. 34PCh. 19 - Show how each of the following transformations...Ch. 19 - Prob. 36PCh. 19 - What reagents would you use to bring about each...Ch. 19 - Prob. 38PCh. 19 - Prob. 39PCh. 19 - 19.40 When the aldol reaction of acetaldehyde is...Ch. 19 - Prob. 41PCh. 19 - Prob. 42PCh. 19 - 19.43 The following reaction illustrates the...Ch. 19 - What is the structure of the cyclic compound that...Ch. 19 - Prob. 45PCh. 19 - Prob. 46PCh. 19 - Prob. 47PCh. 19 - Predict the products from the following reactions....Ch. 19 - Prob. 49PCh. 19 - Prob. 50PCh. 19 - Prob. 51PCh. 19 - Prob. 52PCh. 19 - Prob. 53PCh. 19 - The Perkin condensation is an aldol-type...Ch. 19 - 19.55 (a) Infrared spectroscopy provides an easy...Ch. 19 - Allowing acetone to react with 2 molar equivalents...Ch. 19 - (+) Fenchone is a terpenoid that can be isolated...Ch. 19 - Prob. 58PCh. 19 - Prob. 59PCh. 19 - 19.60 Develop a synthesis for the following...Ch. 19 - 19.61 Provide a mechanism for each of the...Ch. 19 - 19.62 (a) Deduce the structure of product A,...Ch. 19 - Prob. 63PCh. 19 - Prob. 1LGP
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